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hoa [83]
3 years ago
10

The owner of a stereo store wants to advertise that he has many different sound systems in stock. The store carries 6 different

CD​ players, 10 different​ receivers, and 9 different speakers. Assuming a sound system consists of one of​ each, how many different sound systems can he​ advertise?
Mathematics
1 answer:
Orlov [11]3 years ago
6 0

Answer: 540

Step-by-step explanation:

Given : The owner of a stereo store wants to advertise that he has many different sound systems in stock.

Number of different CD​ players =6

Number of different receivers= 10

Number of  different speakers = 9

We are assuming that a sound system consists of one of​ each .

Then by Fundamental principle of counting , we have

The number of different sound systems can he​ advertise = (Number of different CD​ players)x (Number of different receivers) x(Number of  different speakers)

= 6 x10 x 9 =540

Hence, the number of different sound systems can he​ advertise =540

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