Answer:
60
Step-by-step explanation:
-5(2×-6)
-5(-12)
60
It should be correct
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.
h'(t) = -32t + 16
When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.
-32t + 16 = 0
-32t = -16
t = 0.5 seconds
b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.
h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet
If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.
c.) We know that the horse is in the air whenever h(t) is greater than 0.
-16t^2 + 16t = 0
-16t(t-1)=0
t = 0 and 1
So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
Step-by-step explanation:
4+2+2+4+5 - 17
in nearest ten - 100 but i am not sure
Answer:
19
Step-by-step explanation:
1/2*(5+x)*4=48
Answer:
1½ cords per hour
Step-by-step explanation:
A log splitter can split 6/5 cords of wood in 4/5 of an hour.
To find a unit rate, we divide the quantity of cords of wood by the time.
This gives us the complex fraction.
This is the same as
To divide two fractions, we multiply by the reciprocal of the second fraction.
This simplifies to:
The unit rate is 1.5 cords per hour
