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2 years ago

What is the volume of David’s box?

Mathematics

1 answer:

Dmitry [639]2 years ago

4 0

Answer:

H - 6x^7y^15

Step-by-step explanation:

Volume of a rectangular prism (box) is l x w x h

3x^2y^4 * 4x^2y^5 * 1/2x^3y^6

= 6x^7y^15

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In the middle of a park there is a fenced off area in the shape of the fence says is a square. If the area of the fenced off por

Anastasy [175]

Answer:

60 yrds

Step-by-step explanation:

√225

p= distance of all sides ( square p= 4x)

4(15)

7 0

2 years ago

For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.

nordsb [41]

Answer:

<h3>For two events A and B show that P (A∩B) ≥ P (A)+P (B)−1.</h3>

By De morgan's law

$(A\cap B)^{c}=A^{c}\cup B^{c}\\\\P((A\cap B)^{c})=P(A^{c}\cup B^{c})\leq P(A^{c})+P(B^{c}) \\\\1-P(A\cap B)\leq P(A^{c})+P(B^{c}) \\\\1-P(A\cap B)\leq 1-P(A)+1-P(B)\\\\-P(A\cap B)\leq 1-P(A)-P(B)\\\\P(A\cap B)\geq P(A)+P(B)-1$

which is Bonferroni’s inequality

<h3>Result 1: P (Ac) = 1 − P(A)</h3>

Proof

If S is universal set then

$A\cup A^{c}=S\\\\P(A\cup A^{c})=P(S)\\\\P(A)+P(A^{c})=1\\\\P(A^{c})=1-P(A)$

<h3>Result 2 : For any two events A and B, P (A∪B) = P (A)+P (B)−P (A∩B) and P(A) ≥ P(B)</h3>

Proof:

If S is a universal set then:

$A\cup(B\cap A^{c})=(A\cup B) \cap (A\cup A^{c})\\=(A\cup B) \cap S\\A\cup(B\cap A^{c})=(A\cup B)$

Which show A∪B can be expressed as union of two disjoint sets.

If A and (B∩Ac) are two disjoint sets then

$P(A\cup B) =P(A) + P(B\cap A^{c})---(1)\\$

B can be expressed as:

$B=B\cap(A\cup A^{c})\\$

If B is intersection of two disjoint sets then

$P(B)=P(B\cap(A)+P(B\cup A^{c})\\P(B\cup A^{c}=P(B)-P(B\cap A)$

Then (1) becomes

$P(A\cup B) =P(A) +P(B)-P(A\cap B)\\$

<h3>Result 3: For any two events A and B, P(A) = P(A ∩ B) + P (A ∩ Bc)</h3>

Proof:

If A and B are two disjoint sets then

$A=A\cap(B\cup B^{c})\\A=(A\cap B) \cup (A\cap B^{c})\\P(A)=P(A\cap B) + P(A\cap B^{c})\\$

<h3>Result 4: If B ⊂ A, then A∩B = B. Therefore P (A)−P (B) = P (A ∩ Bc) </h3>

Proof:

If B is subset of A then all elements of B lie in A so A ∩ B =B

$A =(A \cap B)\cup (A\cap B^{c}) = B \cup ( A\cap B^{c})$

where A and A ∩ Bc are disjoint.

$P(A)=P(B\cup ( A\cap B^{c}))\\\\P(A)=P(B)+P( A\cap B^{c})$

From axiom P(E)≥0

$P( A\cap B^{c})\geq 0\\\\P(A)-P(B)=P( A\cap B^{c})\\P(A)=P(B)+P(A\cap B^{c})\geq P(B)$

Therefore,

P(A)≥P(B)

8 0

2 years ago

Arnold makes a chart to summarize what happens when light interacts with matter and is reflected. Which idea does Arnold need to

jasenka [17]

Answer:

In diffuse reflection, reflected rays move in different directions.

Step-by-step explanation:

Reflection refers to the bouncing off of light from a surface. Reflection can be regular or diffuse.

Regular reflection occurs when light bounces off a well polished surface while diffuse reflection occurs when light bounces off a rough surface.

During diffuse reflection, light is reflected in different directions.

9 0

2 years ago

Read 2 more answers

Write the slope intercept form of the equation of the line through the given point with the given slope

aleksandrvk [35]

Given that,

Point = (-5,3)

Slope, m = -3/5

To find,

The slope intercept form of the equation of the line.

Solution,

The general form of equation is :

y = mx +b

We have, x = -5, y = 3

So,

$3=\dfrac{-3}{5}(-5)+b\\\\3=-3+b\\\\b = 6$

The equation is :

$y=\dfrac{-3}{5}x+6$

Hence, the required equation is $y=\dfrac{-3}{5}x+6$ .

5 0

2 years ago

Write the number four million, two hundred thirty, seven thousand, three hundred and four hundredths

Anit [1.1K]

There are no tens, ones, or tenths.

4,237,300.04

6 0

3 years ago