A web application starts when a client sends a request to a server
<em>r = 15 cm</em>
<em>formula</em>
<em>V = πr²×h/3</em>
<em>replace</em>
<em>4950 = 22/7×r²×21/3</em>
<em>4950 = 22/7×r²×7</em>
<em>4950 = 22×r²</em>
<em>r² = 4950/22</em>
<em>r² = 225</em>
<em>r = √225</em>
<em>r = √15²</em>
<em>r = 15 cm</em>
Answer:
Check the explanation
Explanation:
// include the necessary packages
import java.io.*;
import java.util.*;
// Declare a class
public class DataReader
{
// Start the main method.
public static void main(String[] args)
{
// create the object of scanner class.
Scanner scan = new Scanner(System.in);
// Declare variables.
boolean done = false;
boolean done1 = false;
float sum = 0;
double v;
int count = 0;
// start the while loop
while (!done1)
{
// start the do while loop
do
{
// prompt the user to enter the value.
System.out.println("Value:");
// start the try block
try
{
// input number
v = scan.nextDouble();
// calculate the sum
sum = (float) (sum + v);
}
// start the catch block
catch (Exception nfe)
{
// input a character variable(\n)
String ch = scan.nextLine();
// display the statement.
System.out.println(
"Input Error. Try again.");
// count the value.
count++;
break;
}
}
// end do while loop
while (!done);
// Check whether the value of count
// greater than 2 or not.
if (count >= 2)
{
// display the statement on console.
System.out.println("Sum: " + sum);
done1 = true;
}
}
}
}
Sample Output:
Value:
12
Value:
12
Value:
ten
Input Error. Try again.
Value:
5
Value:
nine
Input Error. Try again.
Sum: 29.0
Answer:
35
Explanation:
We will be going inside B array, because he was in second place in array E,and will be the first element of array B, so it's 35
E can be understanded as:
E=[[21, 'dog', 'red'],[35, 'cat', 'blue'],[12, 'fish', 'green']], so, you can see array E as array of arrays or so-called two-dimensional array
Answer:
Reorder terms.
y=52x−1
Cancel the common factor of 22.Factor 22 out of −2-2.
y−4=5x2+52⋅(2(−1))y-4=5x2+52⋅(2(-1))
Cancel the common factor.
y−4=5x2+52⋅(2⋅−1)y-4=5x2+52⋅(2⋅-1)
Rewrite the expression.
y−4=5x2+5⋅−1y-4=5x2+5⋅-1
Multiply 55 by −1-1.
y−4=5x2−5
