I think you're asking if it's possible to have a cube root, fifth root, 7th root, etc of a number as a solution to f(x). The answer is yes it's possible.
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Example:
f(x) = x^3 - 29
This function has one real-number root of ![x = \sqrt[3]{29}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B29%7D)
(cube root of 29) and the other two roots are complex or imaginary roots.
22 miles is equal to 1393920 inches
<em><u>Solution:</u></em>
Given that, we have to convert 22 mile to inches
1 Mile (mi) is equal to 63360 inches (in). To convert miles to inches, multiply the mile value by 63360
<em><u>Use the following conversion factor</u></em>
Given is 22 miles
<em><u>Thus, multiply 63360 by 22</u></em>
Thus 22 miles is equal to 1393920 inches
So basically, so start off, let's explain the term "absolute value".
When you want to find the absolute value of something, such as the number 3 in this question, you just look at the number you have.
In this case, you have the number 3, and you want to find two numbers that have an absolute value of 3.
Absolute value is basically always a positive number that's the same number as you had.
You're looking for 3, and there are two numbers with an absolute value of 3.
The numbers are both -3 and 3 since the absolute value guarantees us that the number (or negative number) is always a positive.
Another example: You want to find the absolute value of 113.
The two numbers that have an absolute value of 113 is -113 and 113. Absolute value guarantees the number is always positive, thus you have your two numbers.
Step-by-step explanation:
2 - 7x - 7x + 2
Solving like terms
-14x + 4
Taking 2 as common
-2 (7x - 2)
