Answer:
<u>b = -4, 0</u>
Step-by-step explanation:
<u>Given</u> :
<u>Take b as a common factor.</u>
<u>Solutions</u>
- b = 0
- b + 4 = 0 ⇒ b = -4
- <u>b = -4, 0</u>
Answer:
F. 6s > 4s +8
Step-by-step explanation:
From a reference point at the beginning of the track, Ward's car will be located 4s+8 feet down the track after s seconds. That is, it starts 8 feet down the track, and increases its distance by 4 feet every second.
From the same reference point, Heskey's car will be located 6s feet down the track after s seconds. Its distance starts from zero and is increasing at the rate of 6 feet every second.
For Heskey's distance to exceed Ward's distance you want ...
6s > 4s +8 . . . . . . matches choice F
Answer:
35
Step-by-step explanation:
mutilply the 3 by the 9 subtract dez uts
Answer:
Step-by-step explanation:
Take out 8m as a factor from the top side of the equation. You are left with 
We are asked in the problem to evaluate the integral of <span>(cosec^2 x-2005)÷cos^2005 x dx. The function is an example of a complex function with a degree that is greater than one and that uses special rules to integrate the function via the trigonometric functions. For example, we integrate
2005/cos^2005x dx which is equal to 2005 sec^2005 x since sec is the inverse of cos. The integral of this function when n >3 is equal to I=</span><span>∫<span>sec(n−2)</span>xdx+∫tanx<span>sec(n−3)</span>x(secxtanx)dx
Then,
</span><span>∫tanx<span>sec(<span>n−3)</span></span>x(secxtanx)dx=<span><span>tanx<span>sec(<span>n−2)</span></span>x/(</span><span>n−2)</span></span>−<span>1/(<span>n−2)I
we can then integrate the function by substituting n by 3.
On the first term csc^2 2005x / cos^2005 x we can use the trigonometric identity csc^2 x = 1 + cot^2 x to simplify the terms</span></span></span>
