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3 years ago

9 1/12 = k/9 Solve for K

Mathematics

2 answers:

lesantik [10]3 years ago

5 0

Hope this helps ya :) k= 81.75

Naddik [55]3 years ago

3 0

k/9-1=12

We move all terms to the left:

k/9-1-(12)=0

We add all the numbers together, and all the variables

k/9-13=0

We multiply all the terms by the denominator

k-13*9=0

We add all the numbers together, and all the variables

k-117=0

We move all terms containing k to the left, all other terms to the right

k=117

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Solve each equation? (n+2) ( n+1)= 0

Delicious77 [7]

Answer:

$n=-2,\:n=-1$

Step-by-step explanation:

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7 0

3 years ago

Read 2 more answers

The numbers 0.23350 has how many significant figures?

Alenkinab [10]

Significant figures are the digits that carry meaning to its measurement. Significant figures includes all the numbers excluding all the leading zeros, trailing zeros. All non zero digits are significant. Zeros between the non zero digits are significant. In a decimal number, trailing zeros are significant.

Now, consider the given number 0.23350

Since, in a decimal number all the trailing zeros are significant.

So, in the number 0.23350 there are five significant figures 2,3,4,5 and 0.

Therefore, there are 5 significant figures in the given number.

3 0

3 years ago

Read 2 more answers

Let G denote the centroid of triangle ABC. If triangle ABG is equilateral with side length 2, then determine the perimeter of tr

zhannawk [14.2K]

We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA= $\sqrt{3}$ . Hence CM=GC+GM=3* $\sqrt{3} /$ . Now, since GM is normal to AB, we have by the pythagoeran theorem that:
$AC^2=AM^2+GM^2=BM^2+GM^2=BC^2$
Hence, we calculate from this that AC^2= 28, hence AC=2* $\sqrt{7}$ =BC. Thus, the perimeter of the triangle is 2+4* $\sqrt{7}$ .

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3 years ago

Write the interval using interval notation to describe the set of values shown above.

jenyasd209 [6]

The interval on the number line is (-∞, 2) U [3, ∞)

<h3>How to determine the interval?</h3>

From the number line, we have the following inequalities

x < 2 and x ≥ 3

In inequalities, < and > are represented by brackets i.e. ( and )

While ≤ and ≥ are represented by square brackets i.e. [ and ]

So, we have:

x < 2 and x ≥ 3 = 2) and [3

The intervals must be closed and opened with infinity symbols.

So, we have:

x < 2 and x ≥ 3 = (-∞, 2) and [3, ∞)

Replace and with U

x < 2 and x ≥ 3 = (-∞, 2) U [3, ∞)

Hence, the interval on the number line is (-∞, 2) U [3, ∞)

Read more about interval notation at:

brainly.com/question/13048073

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6 0

1 year ago

What quadratic function f whose only zero is -6

Mrrafil [7]

Answer:

y=(x+6)^2

Step-by-step explanation:

Bc, the root has to be only -6

there fore x=-6

4 0

3 years ago