3 years ago

Write the equation in slope-intercept form that represents the line shown.

Mathematics

1 answer:

slavikrds [6]3 years ago

8 0

I think the answer is y=-1/5x-4 but i’m not sure......

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Which shows the equation below written in the form ax2 + bx + c = 0?

Svetach [21]

Answer:

Step-by-step explanation:

X^2 + 6X + 8 =3

TRANSPOSE 3 TO LEFT

X^2 + 6X + 8 - 3 = 0

CALCULATE

X^2 + 6 X + 5 = 0

3 0

3 years ago

HELP RIGHT NOW ! <br> ASAP !

soldier1979 [14.2K]

Answer:

Its 6

Step-by-step explanation:

7 0

3 years ago

8 - 26r = 892. Solve for r.

marishachu [46]

R = -34

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8 0

3 years ago

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Which point is the image of point R(4, -7) first reflected across the x-axis and then across the y-axis?

nasty-shy [4]

Answer:

(-4, 7)

Step-by-step explanation:

It would be the exact opposite of point R because it was rotated about 180 degrees from it's original location

6 0

3 years ago

What is a1 for the geometric sequence for which a8= -3584 and a3 = 112 ?

jasenka [17]

Answer:

The first term is 28.

Step-by-step explanation:

Given: 8th term of Geometric sequence , $a_8=-3584$

and 3rd term of Geometric Sequence, $a_3=112$

We have to find First term of given geometric Sequence.

Let a be the first term of geometric sequence.

We know that,

$a_n=ar^{n-1}$

So,

$\frac{a_8}{a_3}=\frac{ar^{8-1}}{ar^{3-1}}=\frac{-3584}{112}$

$\frac{r^{7}}{r^{2}}=-32$

$r^5=-32$

$r=-2$

So, $a_3=112$

$a\times(-2)^{2}=112$

$a=\frac{112}{4}=28$

Therefore, The first term is 28.

7 0

3 years ago