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3 years ago

Which shows the equation below written in the form ax2 + bx + c = 0?

Mathematics

1 answer:

Svetach [21]3 years ago

3 0

Answer:

Step-by-step explanation:

X^2 + 6X + 8 =3

TRANSPOSE 3 TO LEFT

X^2 + 6X + 8 - 3 = 0

CALCULATE

X^2 + 6 X + 5 = 0

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The science club sold 24 t-shirts last week and 18 T-shirts this week. What is the percentage of decrease in the number of T-shi

MAVERICK [17]

Answer:

D) 75%

Step-by-step explanation:

75% of 24 = 0.75 x 24 = 18

6 0

3 years ago

What is the area of this triangle?

icang [17]

Answer: 18

Step-by-step explanation: The formula for calculating a triangle’s area is 1/2(base•height). This means that 12•3 is 36, which multiplied by 1/2 is 18.

(Hope this helps)

5 0

3 years ago

Read 2 more answers

In the 2014 - 2015 school year, the mean score on the critical reading of the SAT was 490 with a standard deviation of 102 for j

bonufazy [111]

<u>Answer:</u>

The Ranking Percentile is (B) 97.5%

<u>Explanation :</u>

To find the percentile rank we need to find the z- score. After finding the z-score match this value with the corresponding value in z-score table.

Formula to find the z-score

Z-score= $\frac{\text { scored obtained - mean }(\mu)}{\text { standard deviation }(\sigma)}$

Substituting the values in the above equation, we find

Z-score= $\frac{(694-490)}{102}$ =2

So, the Z-score is +2

Now, the corresponding value of Z-score 2 in the table is 0.9772

or the percentile score is 97.72 ~ 97.5 .

3 0

3 years ago

What are the solutions to the quadratic equation 5x2 + 60x = 0?

Reptile [31]

Answer:

It's A.

Step-by-step explanation:

5x2 + 60x = 0

5x is the GCF so:

5x(x + 12 ) = 0

5x = 0, x + 12 = 0

x =0, x = -12.

6 0

3 years ago

Read 2 more answers

Idk this is supper hard

vlabodo [156]

Answer:

The equation of the line is: y = x + 4

Step-by-step explanation:

When we are given two points passing through a line, we can find the equation of the line by using two - point form.

Two - point form: $\frac{\textbf{y - y}_\textbf{1}}{\textbf{y}_{\textbf{2}} \textbf{-} \textbf{y}_{\textbf{1}}} = \frac{{\textbf{x - x}_\textbf{1}}}{\textbf{x}_{\textbf{2}} \textbf{-} \textbf{x}_{\textbf{1}} }$