Answer:
The answer is "Option A"
Explanation:
In the given java code, a class "Test" is defined, inside the main method try and catch block is used, inside the try block method "p()" is called, that print a message. in this block two catch block is used, that works on "NumberFormatException" and "RuntimeException". In the method "p" declaration, a string variable "s" is defined, that holds double value, that is "5.6", and converts its value into the wrong integer, and other wrong option can be described as follows:
- In option B, it is wrong, it is not followed by after call method.
- In option C, It is not followed by runtime exception, that's why it is incorrect.
- Option D and Option E both were wrong because they can't give run time and compile-time error.
Answer:
"ArithmeticException" is the correct answer for the above question.
Explanation:
Missing Information : The above question does not hold that "what is the output of the program".
- The above question has a class that holds the two functions one function is the main function which calls the other function in a try-catch block.
- The method function holds one run time exception which is 1/0 which is an arithmetic exception.
- It can be handle by the help of an arithmetic class object which is defined in the first catch block.
- Hence the print function of this catch is executed and prints "ArithmeticException".
num1 = float(input("Enter the first number: "))
num2 = float(input("Enter the second number: "))
operation = input("Which operation are you performing? (a/s/m/d) ")
if operation == "a":
print("{} + {} = {}".format(num1, num2, num1+num2))
elif operation == "s":
print("{} - {} = {}".format(num1, num2, num1-num2))
elif operation == "m":
print("{} * {} = {}".format(num1, num2, num1*num2))
elif operation == "d":
print("{} / {} = {}".format(num1, num2, num1/num2))
I hope this helps!
Answer: A. It’s a robust way to find information
Explanation:
Hope this help.
