There are 8 ounces in a cup.
To find how many cups are in a gallon of milk, divide the ounces in a gallon by the ounces in a cup:
A gallon will contain
16 eight-ounce cups.
<h3>
Answer: 2</h3>
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Explanation:
x = number of years
y = height in feet
The equation for the first tree is
y = x+3
The slope is 1 to represent a rate of 1 ft per year of growth. The y intercept of 3 is the starting height. Refer to y = mx+b form.
For the second tree, the equation is:
y = 0.5x+4
This time we have a slope of 0.5 and a y intercept of 4.
Apply substitution to solve for x
y = x+3
0.5x+4 = x+3
0.5x-x = 3-4
-0.5x = -1
x = -1/(-0.5)
x = 2
The trees will be the same height in <u> 2 </u> years.
What will that height be? Plug x = 2 into either equation to find y. We should get the same y value.
y = x+3
y = 2+3
y = 5
Or we could say
y = 0.5x+4
y = 0.5*2+4
y = 1+4
y = 5
We've shown that both equations lead to y = 5 when x = 2. This means that at the 2 year mark, both trees are 5 feet tall. This helps confirm we have the correct x value.
Here, you're mixing scores 85 and 90 with weights X and Y, respectively. You are asked for the ratio of X to Y.
There's a quick way to work mixture problems of all kinds. Write the two components of the mixture on the left. Here, they are 90 and 85. (I usually put the larger one on top.) Put the mixed value in the middle, and form differences along the lines of an X, as shown. The numbers on the right give the relative contributions of the constituents at the same level in the diagram. Here, the ratio of X to Y is shown as 2 to 3.
For some mixture problems, you need to know the proportion of the constituent to the whole. In that case, add the ratio values to get the "whole". For example, here the X class students make up 2/(2+3) = 2/5 of the whole number of students.
For your problem, X/Y = 2/3, corresponding to selection D.
Answer:
Ordered pair 1) (-6,) (1.5) (5,4)
Ordered pair 2) (-4) (-1.5) (-2 ,-2)
Step-by-step explanation:
We use the x cross intersection first and last the crossed paths in bold
