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finlep [7]
3 years ago
12

Please show your work

a1" title="1\frac{2}{3} + 2\frac{3}{4}" alt="1\frac{2}{3} + 2\frac{3}{4}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
Shkiper50 [21]3 years ago
6 0

Answer:

→1 \frac{2}{3}  + 2 \frac{3}{4}  \\  =  \frac{5}{3}  +  \frac{11}{4}  \\  =  \frac{20 + 33}{12}  \\  = \frac{53}{12}\\ =\boxed{4\frac{5}{12}}✓

  • <u>5</u><u>3</u><u>/</u><u>1</u><u>2</u> is the right answer.
Vesna [10]3 years ago
4 0

<u>Steps:</u>

1 2/3 + 2 3/4 can also be written as...

5/3 + 11/4

The LCD is 12 so we make both fractions have a denominator of 12.

That gives us 20/12+33/12

Now you can add the numerators (but leave the denominator the same)

That gives us 53/12, but our simplified version would give us 4 5/12 as our final answer.

<u>Answer:</u>

4\frac{5}{12\\}

Please mark brainliest if that helps!

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slava [35]

Answer:

we will fail to reject the null hypothesis and conclude that the mean pressure is not different from 4.7 psi

Step-by-step explanation:

Let's first define the hypothesis;

Null hypothesis: H0: μ = 4.7

Alternative hypothesis: Ha: μ ≠ 4.7

We have;

Sample size; n = 110

Sample mean; x¯ = 4.6

Variance: σ² = 0.64

Standard deviation; σ = √0.64 = 0.8

Formula for test statistic is;

z = (x¯ - μ)/(σ/√n)

z = (4.6 - 4.7)/(0.8/√110)

z = -0.1/0.0763

z = -1.31

From online p-value from z-score calculator attached, using; z = -1.31, two tailed hypothesis, significance value of 0.1, we have;

P-value = 0.190196

The p-value is greater than the significance value and thus we will fail to reject the null hypothesis and conclude that the mean pressure is not different from 4.7

σ μ

8 0
3 years ago
BRAINLIEST TO CORRECT
ella [17]

9514 1404 393

Answer:

  60

Step-by-step explanation:

Let x represent the number of members last summer. Then 90% more is 1.9x. We are told this is 114, so we have ...

  1.9x = 114

  x = 114/1.9 = 60

There were 60 members last summer.

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Answer:

.2

Step-by-step explanation:

5/25

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3 years ago
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Answer:

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<h2><u><em>hope it helps :D</em></u></h2>

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false

Step-by-step explanation:

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