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dlinn [17]
3 years ago
7

Factor this trinomial. x2 + 2x-3

Mathematics
1 answer:
andre [41]3 years ago
4 0

Answer:(x-1) (x+3)

Step-by-step explanation:

Hope this helps!

You might be interested in
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B49%7D%20" id="TexFormula1" title=" \sqrt{49} " alt=" \sqrt{49} " align="absmiddle
Zinaida [17]
Root of 49

Solutions are 7 and -7

We know that 7 is the square root of 49.

A negative number multiplied by itself gives positive
So -7 is also a square root of 49
5 0
3 years ago
(4y+3)-(2y-9)<br> Simplify. Find the difference.
Nadusha1986 [10]

Answer:

2y+12

Hope this helps

Step-by-step explanation:

5 0
3 years ago
Lines l and k are parallel to each other. mA=120 degrees. and mC=80 degrees. What is the number of degrees in mB??
djverab [1.8K]

Answer:

45

Step-by-step explanation:

6 0
3 years ago
If the weight of a package is multiplied by 3/4 the result is 54 pounds find the weight of the package?
Ede4ka [16]

Answer:

72

Step-by-step explanation:

In order to find the solution to this problem, you would first need to divide 54 by 3, than multiply by 4. You could also multiply 54 by the reciprocal of 3/4, which is 4/3.

6 0
3 years ago
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
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