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3 years ago

Use the distributive property to simplify -5(-2f-6)

Mathematics

2 answers:

nydimaria [60]3 years ago

7 0

-5(-2f-6)

-5•-2f = 10f
-5•-6=30

(negative • negative = positive)

10f+30 is your answer

Angelina_Jolie [31]3 years ago

4 0

-5(-2f-6)

distribute by multiplying -5 by everything inside the parenthesis

-5 * -2f = 10f

-5 *-6 = 30

so you get 10f+30

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Ulleksa [173]

Answer:

(a)3

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Step-by-step explanation:

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=1/6 X 18

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P(the number 10 appear)=1/10

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P(red)=2/10

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If the card is picked 65 times and replaced each time.

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3 years ago

Put these in order from least to greatest!: 88/25, 3.551, 3.88, 3 11/20

DedPeter [7]

Rewrite all 4 numbers as decimals to compare them:

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Now arrange them in the correct order:

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3 years ago

Read 2 more answers

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ehidna [41]

Answer:

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Step-by-step explanation:

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3 years ago

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

Mrac [35]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have $DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute $A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

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