Answer:
Step-by-step explanation:
where is the pic of the problem
Answer:
300ft
Step-by-step explanation:
Answer:
128
Step-by-step explanation:
just multiply 64 by 2..
Answer:
See below.
Step-by-step explanation:
1)
So we have:
![\exists x\in\mathbb{N},y\in\mathbb{Z}|x^2=y^2](https://tex.z-dn.net/?f=%5Cexists%20x%5Cin%5Cmathbb%7BN%7D%2Cy%5Cin%5Cmathbb%7BZ%7D%7Cx%5E2%3Dy%5E2)
This can be interpreted as:
"There exists a natural number <em>x</em> and an integer <em>y</em> such that x² is equal to y²."
2)
So we want even numbers are in the set of integers.
![\{2n:n\in\mathbb{Z}\}\in\mathbb{Z}](https://tex.z-dn.net/?f=%5C%7B2n%3An%5Cin%5Cmathbb%7BZ%7D%5C%7D%5Cin%5Cmathbb%7BZ%7D)
This is interpreted as:
"The set of even numbers (2n such that n is an integer) is in the set of integers"
Answer:
The zero is x = 3/2 = 1.5
Step-by-step explanation:
We recognize that the trinomial 4 x^2 - 12 x + 9 is a perfect square trinomial, which comes from the following squared binomial:
(2 x - 3)^2
Therefore, the zeros are the x-values that verify the following:
(2 x - 3)^2= 0
that is (2 x - 3) = 0 and solving for "x":
2 x = 3
x = 3 / 2
x = 1.5