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scoundrel [369]

3 years ago

13

CAN ANYONE HELP PLEASE I NEED THIS DONE BY TODAY!! I WILL MARK YOU BRIANLYIST.

1 answer:

bulgar [2K]3 years ago

7 0

I have no idea my dude sorry

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Gennadij [26K]

Answer:

3.675 m

Explanation:

$a_{x} =0$ $v_{xo}=100$ $a_{y} =-g$ $v_{yo}=0$

X-direction | Y-direction

$R=x_{o}+ v_{xo} t$ | $y=y_{o}+v_{yo}t+\frac{1}{2}a_{y}t^2$

$75=100t$ | $y=0+0+\frac{1}{2} (9.8)(0.75)$

$\frac{75}{100} =t$ | $y=3.675 m$

$0.75s=t$

Hope it helps

3 0

3 years ago

Which component measures the potential difference across a branch in a circuit? A. switch B. resistor C. ammeter D. voltmeter

NNADVOKAT [17]

Answer:

Voltmeter

Explanation:

7 0

3 years ago

What is a cone of depression

Thepotemich [5.8K]

A Cone of Depression occurs when a well pumps water from a certain area and causes a depression in a cone shape in the water table.

Hope this helps! :)

if you get it correct Brainliest is greatly appreciated

7 0

4 years ago

The cost of cleaning up pollution in a stream is given by C = 37000 100−p, where C is the cost in dollars to clean p percent of

barxatty [35]

Answer:

$0\leq p$

Explanation:

We have in the problem the following expression,

$c=3700(100-p)$

Where

c= cost in dollar

p= is percent of stream (Which $p\geq 0$ )

P must be greater or equal to 0 but as well must be less than 100%

so we define the interval

$0\leq p$

If the value were equal to 100 the cost would be the equivalent of 0 and there would be no profit / gain.

4 0

3 years ago

A Federation starship (8.5 ✕ 106 kg) uses its tractor beam to pull a shuttlecraft (1.0 ✕ 104 kg) aboard from a distance of 14 km

natima [27]

Force applied by the beam is given as

$F = 4 * 10^4 N$

now the acceleration of starship is given as

$a_1 = \frac{F}{m_1}$

$a_1 = \frac{4 * 10^4}{8.5 * 10^6} = 4.7 * 10^{-3} m/s^2$

acceleration of space craft will be given as

$a_2 = \frac{F}{m_2}$

$a_2 = \frac{4 * 10^4}{1 * 10^4} = 4 m/s^2$

now the relative acceleration is given as

$a = a_1 + a_2 = 4.0047 m/s^2$

now the distance between them is d = 14000 m

now we can use kinematics to find the time to cover this distance

$d = \frac{1}{2} at^2$

$14000 = \frac{1}{2}*4.0047* t^2$

$t = 83.62 s$

now we have to find the distance moved by starship

$d_1 = \frac{1}{2} a_1t^2$

$d_1 = \frac{1}{2}*0.0047* 83.62^2$

$d_1 = 16.4m$

so it will move by 16.4 m distance

4 0

3 years ago