From equations of motion,
v^2 = u^2 + 2as ----- v = final velocity, u = initial velocity, a = acceleration, s = distance covered.
Using the vales given;
v^2 = 15^2 + 2*4*50 = 625
v = Sqrt (625) = 25 m/s
(a) could possibly become a vector
Answer:16.096
Explanation:
Given
mass of dog
mass of boat
distance moved by dog relative to ground=
distance moved by boat relative to ground=
Distance moved by dog relative to boat=7.8m
There no net force on the system therefore centre of mass of system remains at its position
0=
0=
i.e. boat will move opposite to the direction of dog
Now
substitutingvalue
now the dog is 22.5-6.403=16.096m from shore
Answer:
(a) the height in the open water column is: 18.15 (ft), (b) the gauge pressure acting on the bottom tank surface AB is: 8.73 (Psi) and (c) the absolute pressure of the air in the top of the tank with local atmospheric pressure at 14.7 Psi will be: 21.7 (Psi).
Explanation:
We need to apply the Pascal's Law, () where P is pressure, γ is the specific weight of the fluid and h is the height of the column of fluid, to find the pressure at differents points in the tank (see attached). First we need to assume a property of the water called specific weight as: 62.4 (lbf/ft^3) or 0.03612 (lbf/in^3). Then knowing that 1 feet as the same as 12 inches and appling Pascal's Law, we get: and the other hand, we have: and knowing that the pressure at point C and point D are the same, we can find the h as:, so getting h=217.75(in) or 18.15(ft) (a). Now similarly to find the gauge pressure acting on the bottom of the tank surface AB we can apply Pascal's Law as: (b). Finally we can find the absolute pressure of the air in the top of the tank, assuming a local atmospheric pressure as 14.7 (Psi) so: (c).
Answer:
The wavelength is
The frequency is
Explanation:
From the question we are told that
The distance between two successive crest is 0.80 m
The velocity is v = 2.6 m/s
Generally wavelength is the distance between two successive crest
So
Now the frequency is mathematically represented as