The velocity of the package after it has fallen for 3.0 s is 29.4 m/s
From the question,
A small package is dropped from the Golden Gate Bridge.
This means the initial velocity of the package is 0 m/s.
We are to calculate the velocity of the package after it has fallen for 3.0 s.
From one of the equations of kinematics for objects falling freely,
We have that,
v = u + gt
Where
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
and t is time
To calculate the velocity of the package after it has fallen for 3.0 s
That means, we will determine the value of v, at time t = 3.0 s
The parameters are
u = 0 m/s
g = 9.8 m/s²
t = 3.0 s
Putting these values into the equation
v = u + gt
We get
v = 0 + (9.8×3.0)
v = 0 + 29.4
v = 29.4 m/s
Hence, the velocity of the package after it has fallen for 3.0 s is 29.4 m/s
Learn more here: brainly.com/question/13327816
1) Length of the wire.
2) Thickness of the wire.
3) Temperature.
4) Type of metal.
Hope this helps!
-Payshence
Answer:
D.
a heat force generated by the flames
Explanation:
Im not sure if that is right. the answer also maybe C.
Answer:
1. E=5320.3J
2. E= 1773.45J
3. E=6.76*10^{-21}J
4. E=2.25*10^{-21}J
Explanation:
1. the thermal energy is given by the formula
where KB is the Boltzmann's constant, T is the temperature and N is the number of molecules in the system.
2. Each degree of freedom contains one half of the total energy. Hence, the energy for one degree of freedom is
3.
4.
Hope this helps!!