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Jobisdone [24]
3 years ago
14

Rex decides to launch a priceless vase into the air at a 90-degree angle. The initial velocity vase is +7.0 m/s. Dylan claims th

at the vase would achieve a higher height if it were launched at a 45-degree a Dylan correct? A. Dylan is correct because a 45-degree launch angle results in the largest vertical range B. Dylan is correct because larger launch angles result in a smaller vertical range. C. Dylan is incorrect because a 90-degree and 45-degree launch angle result in the same range. D. Dylan is incorrect because a 90-degree launch angle results in the largest vertical range​

Physics
1 answer:
Sergeu [11.5K]3 years ago
6 0

Answer:

D. Dylan is incorrect because a 90-degree launch angle results in the largest vertical range​

Explanation:

Projectile is the motion of an object thrown into space. When an object is thrown into space, the only force which acts on it is the acceleration due to gravity.

An object thrown into space would reach maximum height (vertical range) if it is launched at an angle of 90 degrees. For maximum horizontal range, the object needs to be launched at an angle of 45 degrees.

Therefore Dylan is incorrect because a 90-degree launch angle results in the largest vertical range​

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A pickup truck is traveling down the highway at a steady speed of 30.1 m/s. The truck has a drag coefficient of 0.45 and a cross
Sav [38]

Answer:

The energy that the truck lose to air resistance per hour is 87.47MJ

Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

F_D=\frac{1}{2}\rhoC_dAV^2

Our values are:

V=30.1m/s

C_d=0.45

A=3.3m^2

\rho=1.2kg/m^3

Replacing,

F_D=\frac{1}{2}(1.2)(0.45)(3.3)(30.1)^2

F_D=807.25N

We need calculate now the energy lost through a time T, then,

W = F_D d

But we know that d is equal to

d=vt

Where

v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

W=(807.25N)(30.1m/s)(3600s/1hr)

W=87.47*10^6J (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

4 0
3 years ago
What type of wavelength can we feel as heat and it is used to change the television channel with a remote?
enot [183]

Answer:

d)infrared waves

Explanation:

A remote control uses light waves just beyond the visible spectrum of light—infrared light waves—to change channels on your TV. This region of the spectrum is divided into near-, mid-, and far-infrared.

5 0
3 years ago
A jet plane traveling 1890 km/h (525 m/s) pulls out of a dive by moving in an arc of radius 5.20 km. What is the plane's acceler
Tema [17]

Answer:

Acceleration of the plane, a = 5.4 g

Explanation:

It is given that,

Speed of the jet plane, v = 1890 km/h = 525 m/s

Radius of the arc, r = 5.20 km = 5200 m

The plane is moving in the circular path, the centripetal acceleration will act on it. It is given by :

a=\dfrac{v^2}{r}

a=\dfrac{(525\ m/s)^2}{5200\ m}

a=53.004\ m/s^2

We know that, the value of g is, g=9.8\ m/s^2

\dfrac{a}{g}=\dfrac{53.004\ m/s^2}{9.8\ m/s^2}=5.4

a=5.4\times g

So, the acceleration of the plane is 5.4 g. Hence, this is the required solution.

6 0
3 years ago
Read 2 more answers
The diagram below show the alignment of the sun moon and earth
Sphinxa [80]

Answer:

A

Explanation:

5 0
3 years ago
Calculate the hydrostatic difference in blood pressure between the brain and the foot in a person of height 1.93 m. The density
Slav-nsk [51]

Answer:

Explanation:

Given: Density of blood = 1.03 × 10³ Kg/m³, Height =  1.93 m g = 9.8 m/s²

pressure at the brain is equal to atmospheric pressure. = Hydro-static

pressure(ρ₀)

∴ pressure of the foot = pressure of the brain(ρ₀) + ( density of blood × acceleration due to gravity × height)(ρgh)

Hydro-static pressure = pressure at the feet- pressure at the brain(ρ₀)

Hydro-static pressure (Δp) = (ρgh + ρ₀) - ρ₀ = ρgh

Hydro-static pressure = 1.03 × 10³ × 9.8 × 1.93 = 1.948 × 10⁴ Pa

∴  Hydro-static pressure ≈ 1.95 × 10⁴ Pa

3 0
3 years ago
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