Ask Your Teacher A flight attendant pulls her 69 N flight bag a distance of 268 m along a level airport floor at a constant velo
1 answer:
Answer:
a) W = 5360 J b) μ = 0.29
Explanation:
a) The work is, bold indicate vectors
W = F. d = F d cos T
W = 40 268 cos 60
W = 5360 J
b) The force of friction and opposes the movement of the body and if the speed of the body is constant implies that the external force in the direction of the movement is equal to the force of friction, or which work is the same
= -5360J
The negative sign is because the force of friction is contrary to the direction of movement
c) Let's write the work of the friction force
= fr d cos 180
fr = μ N
Since the body is on a horizontal surface, from Newton's second law on the Y axis
N-W = 0
N = W
fr = μ W
= - μ W d
μ = - / W d
μ = - (-5360) / 69 268
μ = 0.29
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0.000025 → 2.5 × 10⁻⁵ → 2.5E-5
<h3>Further explanation</h3>Scientific notation represents the precise way scientists handle exceptionally abundant digits or extremely inadequate numbers in the product of a decimal form of number and powers of ten. Put differently, such numbers can be rewritten as a simple number multiplied by 10 raised to a certain exponent or power. It is a system for expressing extremely broad or exceedingly narrow digits compactly.
Scientific notation should be in the form of
where
The number 'a' is called 'mantissa' and 'n' the order of magnitude.
From the key question that is being asked, we face the standard form of 0.000025.
The coefficient (or mantissa), i.e. 25, is still outside of 1 ≤ a < 10. Both the numerator and denominator are divided by 10.
The denominator consists precisely of five zero digits.
Hence, 0,000025 is written in scientific notation as
The inverse of scientific notation is the standard form. To promptly change scientific notation into standard form, we reverse the process, move the decimal point to the right or left. This expanded form is called the standard form.
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Keywords: which is, a correct representation, 0.000025, in scientific notation, expanded form, exponent, base, standard form, mantissa, the order of magnitude, power, decimal, very large, small, figures, abundant digits, inadequate
The acceleration is found to be 2 m/s², final velocity after 10 seconds is 20 m/s and the final position after 10 seconds is 100 m away from the starting point.
Answer:
Explanation:
As per Newton's second law of motion, acceleration of any object is directly proportional to the net external unbalanced force acting on that object and inversely proportional to the mass of the object.
Since there are two forces acting on the box in opposite direction, the net force will be the difference of horizontal and frictional force acting on the object.
Net force = Horizontal force - Frictional force = 18 N - 8 N = 10 N.
Now, from second law of motion,
So, acceleration = 10 N /5 kg = 2 m/s².
Since, acceleration exerted by the box is found to be 2 m/s², we can determine the final velocity of the object after 10 seconds using the first equation of motion.
v = u + at, Here v is the final velocity and u is the initial velocity which is zero for the present case. Other parameters like a is found to be 2 m/s² and time is 10 seconds.
So Final velocity v = 0+(2×10)=20 m/s.
And the final position can be determined using the second equation of motion.
s = ut+1/2at²
Final position = (0×10)+(0.5×2×10×10)= 100 m.
So the final position is 100 m.
Thus, the acceleration is found to be 2 m/s², final velocity after 10 seconds is 20 m/s and the final position after 10 seconds is 100 m away from the starting point.