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icang [17]
3 years ago
10

Help pleaseee!!!!!!!​

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
5 0

Answer:

14 in. hope this helps good luck

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X/-9 +9=8 please help me
nekit [7.7K]
X = 9   X/-9 +9=8  9<span>/-9 +9=8 </span>
6 0
3 years ago
Read 2 more answers
Please help this is easy for anyone with more than 2 brain cells
Anarel [89]

Answer:

-9

Step-by-step explanation:

The answer is -9 because you always take away a nine for ex 47-9 is 38

8 0
3 years ago
Cynthia is in the process of constructing two tangent line segments from a point outside circle O to circle O as shown. Which li
Allisa [31]

Answer:

(B) Segments MA and MB

Step-by-step explanation:

The tangent to the circle at a point is perpendicular to the radius of the circle drawn to the point of tangency.

Tangent at a point is unique.

Since there can be no two tangents at a point on circle, the options (b) and (c) are ruled out.

Now, if OA is perpendicular to MA, MA is the tangent else if OA is perpendicular to PA, PA is the tangent. Same is the case with point B.

Tangents from the same external point has same length.

MA = MB since they are the radii of the same circle with center M.

Hence, MA and MB meet all the requirements of the tangents.


8 0
4 years ago
Read 2 more answers
Harry invests 6000 in the savings account that account payis 3.4% compound interest per year what out the value of his investmen
Tcecarenko [31]

Use the compound interest formula:

A=P(1+R)^3

A=6000(1+.034)^3 Make sure to change percent to decimal

A=6000(1.034)^3

A=6000(1.105507304)

A=6633.04

The total after interest of 3 years would be $6,633.04.

3 0
3 years ago
What is a counterexample of the statement “all square roots are irrational”
skad [1K]

Rather than trying to guess and check, we can actually construct a counterexample to the statement.

So, what is an irrational number? The prefix "ir" means not, so we can say that an irrational number is something that's not a rational number, right? Since we know a rational number is a ratio between two integers, we can conclude an irrational number is a number that's not a ratio of two integers. So, an easy way to show that not all square roots are irrational would be to square a rational number then take the square root of it. Let's use three halves for our example:

\sqrt{(\frac{3}{2})^2}=\\\sqrt{\frac{9}{4}}=\\\frac{3}{2}

So clearly 9/4 is a counterexample to the statement. We can also say something stronger: All squared rational numbers are not irrational number when rooted. How would we prove this? Well, let \frac{a}{b} be a rational number. That would mean, \frac{a^2}{b^2}, would be a/b squared. Taking the square root of it yields:

\sqrt{\frac{a^2}{b^2}}}=\\ \frac{\sqrt{a^2}}{\sqrt{b^2}}=\\ \frac{a}{b}

So our stronger statement is proven, and we know that the original claim is decisively false.

3 0
3 years ago
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