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Thepotemich [5.8K]

3 years ago

12

The following sequence has first five terms as: -20, -17, -14, -11, -8, .......... Find an expression for the nth term of the se

quence

1 answer:

Maslowich3 years ago

4 0

Answer:

a(n) = -20 + 3(n - 1)

Step-by-step explanation:

a(n) = -20 + 3(n - 1)

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Hi can someone solve the inequalities?

vodomira [7]

8y - 5 < 3

8y < 5+3

8y<8

y<1

3p + 2 > -10

3p>-10-2

3p> -12

p>-4

-2 > m/6 -7

- m/6>+2-7

Multiply each member by 6

-m >-42+12

-m>-30

m<30

8 0

2 years ago

Yeahhh, please help :,) :DDDD

Tamiku [17]

Answer:

-46

Step-by-step explanation:

4 0

3 years ago

1.Find x,y and z in the figure. 2. find the x and y in the figure

STALIN [3.7K]

$\\ \sf\longmapsto x+2x+90=180$

$\\ \sf\longmapsto 3x+90=180$

$\\ \sf\longmapsto 3x=180-90$

$\\ \sf\longmapsto 3x=90$

$\\ \sf\longmapsto x=\dfrac{90}{3}$

$\\ \sf\longmapsto x=30$

Now

$\\ \sf\longmapsto x=2y$ (Opposite interior angles)

$\\ \sf\longmapsto 2y=30$

$\\ \sf\longmapsto y=\dfrac{30}{2}$

$\\ \sf\longmapsto y=15$

And

$\\ \sf\longmapsto x+z=180$

$\\ \sf\longmapsto z+30=180$

$\\ \sf\longmapsto z=180-30$

$\\ \sf\longmapsto z=150$

6 0

2 years ago

Read 2 more answers

Let r(t)=⟨t2,1−t,4t⟩. calculate the derivative of r(t)⋅a(t) at t=5, assuming that a(5)=⟨−4,4,−5⟩ and a′(5)=⟨−5,9,3⟩

erastovalidia [21]

$\mathbf r(t)=\langle t^2,1-t,4t\rangle$
$\implies\mathbf r'(t)=\langle 2t,-1,4\rangle$

$\dfrac{\mathrm d(\mathbf r(t)\cdot\mathbf a(t))}{\mathrm dt}\bigg|_{t=5}=\mathbf r'(5)\cdot\mathbf a(5)+\mathbf r(5)\cdot\mathbf a'(5)$
$=\langle10,-1,4\rangle\cdot\langle-4,4,-5\rangle+\langle25,-4,20\rangle\cdot\langle-5,9,3\rangle$
$=(-40-4-20)+(-125-36+60)$
$=-165$

6 0

3 years ago

A parabola and its focus are shown on the graph. The vertex of the parabola is at (0,0).

natulia [17]

Answer:

y = -3

Step-by-step explanation:

the length from directrix to vertex is equal to the length from focus to the vertex.

4 0

3 years ago

Read 2 more answers