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2 years ago

WHICH TABLE IS A FUNCTION? TABLE A TABLE B NEITHER BOTH

Mathematics

2 answers:

jeka942 years ago

7 0

Answer:

I honestly think its neither

Alexandra [31]2 years ago

3 0

I believe it neither

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Anyone knows this ?

nata0808 [166]

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3 years ago

WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!! WHAT IS THE AMPLITUDE OF THIS FUNCTION

nika2105 [10]

your answer should be three.

~iwa-chan

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3 years ago

A regular triangular pyramid has a base area of 31.5 mm2

Yuri [45]

Answer:

maybe do the math

Step-by-step explanation:

7 0

3 years ago

A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the prob

UkoKoshka [18]

Answer:

The probability that 8 mice are required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

$P(X=r)=^nC_r p^rq^{n-r}$

Where, p is the probability of success $p=\frac{2}{7}$

q is the probability of failure q=1-p, $q=1-\frac{2}{7}=\frac{5}{7}$

n is total number of trials n=8

r=3

Substitute the values,

$P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}$

$P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}$

$P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}$

$P(X=3)=0.2428$

Therefore, the probability that 8 mice are required is 0.2428.

5 0

3 years ago

The sum of 2 times a number and 3 is 6

barxatty [35]

Is there a question or is this it ?
it basically answers itself because 2 times 3 is 6

6 0

3 years ago

Read 2 more answers