Answer:
The answer would be 22/12 or 1 and 11/12
Step-by-step explanation:
1/2+2/3+3/4
First get common denominators so you have a denominator of 12 so 6/12+8/12+9/12
Add those together and you get 23/12 but you have to subtract one because that's what the problem says so you get 22/12
Answer:
the d is right one look this img
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
The lifetime (in hours) of a 60-watt light bulb is a random variable that has a Normal distribution with σ = 30 hours. A random sample of 25 bulbs put on test produced a sample mean lifetime of = 1038 hours.
If in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99% confidence, how many randomly selected 60-watt light bulbs should be tested to achieve this result?
Given Information:
standard deviation = σ = 30 hours
confidence level = 99%
Margin of error = 6 hours
Required Information:
sample size = n = ?
Answer:
sample size = n ≈ 165
Step-by-step explanation:
We know that margin of error is given by
Margin of error = z*(σ/√n)
Where z is the corresponding confidence level score, σ is the standard deviation and n is the sample size
√n = z*σ/Margin of error
squaring both sides
n = (z*σ/Margin of error)²
For 99% confidence level the z-score is 2.576
n = (2.576*30/6)²
n = 164.73
since number of bulbs cannot be in fraction so rounding off yields
n ≈ 165
Therefore, a sample size of 165 bulbs is needed to ensure a margin of error not greater than 6 hours.
Answer:
3
Step-by-step explanation:
Answer:
![3m\sqrt[5]{2m^4p^4}](https://tex.z-dn.net/?f=3m%5Csqrt%5B5%5D%7B2m%5E4p%5E4%7D)
Step-by-step explanation:
We want to find the fifth root of
. In order to do so, we need to factorise
Let's factorise 486 first:
486 = 2 * 243 = 2 * 
Ah, we see that
can be taken out and becomes 3 outside of the 5th root since the 5th root of
Now look at the variables. We see that since we have p^"4", whose exponent is less than 5, it's impossible for us to write it as a power of 5, so we leave this in the root.
We also have m^"9", which can be written as m^"5" * m^"4". Again, we see that the m^"4" term will have to remain inside the root, but we can take out the m^"5", which becomes m.
Our final answer is thus:
.
<em>~ an aesthetics lover</em>