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2 years ago

Find the volume help me pls and thank

Mathematics

2 answers:

Inga [223]2 years ago

8 0

Answer:

Volume = 14.333

Step-by-step explanation:

jok3333 [9.3K]2 years ago

8 0

Answer: 14.34 cm^3

Step-by-step explanation:

V = lwh

V = 3.2 cm x 2.8 cm x 1.6 cm

V = 14.34 cm^3

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Evaluate the expression 0.03^3

Vinvika [58]

The given expression is,

$0.03^3$

So, expanding we have,

$0.03^3=0.03\times0.03\times0.03=\text{0}.000027$

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8 months ago

The scale drawing of a concrete pad has a length of 9.1 cm, a depth of 2.2 cm and a width of 3.8 cm.

pogonyaev

Answer:

242 cm

Step-by-step explanation:

1. Find the scale factor

A scale factor (SF) is the ratio of two corresponding lengths in similar figures.

SF = actual distance/scale distance

If the scale width is 3.8 cm,

SF = 418 cm/3.8 cm = 110

2. Calculate the actual depth

110 = actual depth/2.2 cm

Actual depth = 110 × 2.2 cm = 242 cm

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2 years ago

The circumference of a circle is 10pi cm. What is the Radius of the circle?

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3 years ago

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What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$