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3 years ago

Help? I’ll mark u brainliest

Mathematics

1 answer:

andrew-mc [135]3 years ago

6 0

Answer:

11 because adjacent is basically next to and NKL is 12

Step-by-step explanation:

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James designed a game of chance which involves identical balls numbered from 1 to 50. He selected 5 balls at random and found th

Bad White [126]

It ......... is .......... 38 .........

3 0

2 years ago

What is the probability that a red or green marble will be selected from a bag containing 9 red marbles, 6 blue marbles, 7 green

lara31 [8.8K]

Answer: $\bold{\dfrac{16}{33} = 48\%}$

Step-by-step explanation:

Red or Green

$=\dfrac{red}{total}+\dfrac{green}{total}$

$=\dfrac{9}{33}+\dfrac{7}{33}$

$=\dfrac{16}{33}$

≈ 48%

4 0

3 years ago

A ________ function specifies the relationship between the demand for a product LaTeX: x and the price of the product LaTeX: p.

Archy [21]

Answer:

Price demand function

Step-by-step explanation:

The price demand function is the function in which there is a relationship between the demand and the price of the product

The Price demand function is

$= Price \times demand$

$= p \times x$

hence, the price demand function represents that there is a relationship that lies between the demand and the price

3 0

2 years ago

What is the solution to the inequality? -3x < 24

Paraphin [41]

Answer:

x > -8

Step-by-step explanation:

Divide both sides by -3 to get x by itself. Dividing by a negative number will switch the less-than symbol to a greater-than symbol. -3x ÷ -3 = x and 24 ÷ -3 = -8. When you put it all together, you get x > -8

8 0

2 years ago

Radioactive Decay:

Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

Answer: The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

Step-by-step explanation:

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}$

The formula used to calculate the time period for a first order reaction follows:

$t=\frac{2.303}{k}\log \frac{a}{(a-x)}$

where,

k = rate constant = $0.01506days^{-1}$

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

$t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days$

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0

2 years ago