Answer:
1.When one side of the tug-of-war rope has a larger net force than the other side then the basket in the middle will be pulled to whichever side has a larger net force. As the sum of forces increases, the speed of the cart goes faster throughout the tug of war.
2.When both sides of the tug-of-war rope are made equal in force than the rope does not move at all. There is a mass of 350 N on both sides of the cart. The net force in this scenario is 0 because there is no difference in mass.
3.With the first example, the speed odometer gets up to right next to the “S” in speed. With one small person verse all four on the other side, the speed odometer moves all the way past halfway to the d in Speed.
4.The objects selected will vary.
5.The chart will look different depending on the ratio of weights that you put on the skateboard. The answers provide what a chart might look like.
Trial number Mass on Skateboard Applied Force by Person Speed When Let Go
1 330 kg 200 N 3.3 m/s
2 100 kg 200 N 9.2 m/s
3 340 kg 200 N 1.1 m/s
6.The relationship between speed and force is direct because regardless of the mass on the skateboard and the force involved, they continue to increase. The greater the force applied to the skateboard when it is released, the higher the speed of the skateboard.
7.The relationship between mass and speed (with constant force) is indirect. The higher the mass that needs to be pushed, the lower the starting speed is of the skateboard.
8.The longer the force is applied to the skateboard, the higher the speed of the skateboard will be. Even with the heaviest possible skateboard, the speed will max out after a certain period of time. The time needed to do this is shorter when the mass is lighter, indicating a direct relationship between the variables.
9.Your chart may look different based on the results from your first trial completed in question 5.
Trial number Mass on Skateboard Applied Force by Person Friction Speed When Let Go
1 Same as Trial #1, Question 5 Same as Trial #1, Question 5 None 2.7 m/s
2 Same as Trial #1, Question 5 Same as Trial #1, Question 5 Medium 0.0 m/s
3 Same as Trial #1, Question 5 Same as Trial #1, Question 5 Lots 0.0 m/s
10.The relationship between speed and friction is indirect because as the friction increases the speed decreases.
11.The object stays still when there is too much friction applied to the equation with the mass and applied force.
12.The relationship between force and acceleration is directly proportional. Whatever the force is that is applied to the object, the acceleration of that object increased by the same factor.
Explanation:
