Answer:
36 J
Explanation:
Let's start off with the Kinetic Energy formula: 1/2m
So to find the <em>change</em> in Kinetic Energy, you would first have to find the Kinetic Energy in the beginning and in the end.
*Note: Mass: you incorrectly wrote weight = 6 kg- because weight is a force you have to write 6 Newtons. If you are talking about the <em>mass</em>, you would write 6 kg. If you are talking about weight, you would write 6 Newtons. The difference will make significant changes to the answer, so I will give you the answer for both.
If 6 kg is the MASS:
Beginning: find the kinetic energy.
Plug in all parts of the formula: 1/2mv^2 = (6)(2 squared)=
(6)(4)= 12 J
End: find the kinetic energy.
Plug in all parts of the formula: 1/2mv^2=(6)(4 squared)=
(6)(16)= 48 J
Answer:
36 J
If 6 kg is the WEIGHT:
We know that the weight formula is mg, or mass times acceleration due to gravity (which is always 9.8 m/s^2). Plug in the numbers:
Weight = mass x acceleration due to gravity
6 = mass x 9.8
6 = 9.8m
*Divide both sides*
mass = 0.6 kg
Now, we can use the mass to find the kinetic energy.
Beginning: find the Kinetic Energy
Plug in all parts of the formula: 1/2mv^2 = (0.6)(2 squared)=
(0.6)(4)= 1.2 J
End: find the Kinetic Energy
Plug in all parts of the formula: 1/2mv^2=(0.6)(4 squared)=
(0.6)(16)= 4.8 J
Answer:
3.6 J
(this answer is not very feasible, so 36 J is the way to go. But just remember, don't mix up weight and mass again- as you can see, they lead to different answers!)
Answer:
The magnitude of the net force is √2F.
Explanation:
Since the two particles have the same charge Q, they exert the same force on the test charge; both attractive or repulsive. So, the angle between the two forces is 90° in any case. Now, as we know the magnitude of these forces and that they form a 90° angle, we can use the Pythagorean Theorem to calculate the magnitude of the resultant net force:
Then, it means that the net force acting on the test charge has a magnitude of √2F.
Answer:
Velocity, v = 0.239 m/s
Explanation:
Given that,
The distance between two consecutive nodes of a standing wave is 20.9 cm = 0.209 m
The hand generating the pulses moves up and down through a complete cycle 2.57 times every 4.47 s.
For a standing wave, the distance between two consecutive nodes is equal to half of the wavelength.
Frequency is number of cycles per unit time.
Now we can find the velocity of the wave.
Velocity = frequency × wavelength
v = 0.574 × 0.418
v = 0.239 m/s
So, the velocity of the wave is 0.239 m/s.
Explanation:
It is given that,
Mass of golf club, m₁ = 210 g = 0.21 kg
Initial velocity of golf club, u₁ = 56 m/s
Mass of another golf ball which is at rest, m₂ = 46 g = 0.046 kg
After the collision, the club head travels (in the same direction) at 42 m/s. We need to find the speed of the golf ball just after impact. Let it is v.
Initial momentum of golf ball,
After the collision, final momentum
Using the conservation of momentum as :
v = 63.91 m/s
So, the speed of the golf ball just after impact is 63.91 m/s. Hence, this is the required solution.