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Georgia [21]
3 years ago
11

When reacting Na with Cl2 , we calculated that the theoretical yield should be 12.5 grams. Our actual yield was 13.0 grams. What

is the percent yield?
Chemistry
1 answer:
vaieri [72.5K]3 years ago
5 0

Answer:

\boxed {\boxed {\sf 104 \%}}

Explanation:

Percent ratio is the ratio of the actual yield to the theoretical yield. The formula is below.

Percent \ Yield} = \frac{{Actual \ Yield}}{{Theoretical \ Yield}} \times 100 \%

The reaction of sodium and chlorine should theoretically yield 12.5 grams, but the actual yield was 13.0 grams.

  • actual yield= 13.0 g
  • theoretical yield = 12.5 g

Substitute these values into the formula.

Percent \ Yield} = \frac{{13.0 \ g }}{{12.5 \ g}} \times 100 \%

Divide.

Percent \ Yield} = 1.04 \times 100 \%

Multiply.

Percent \ Yield= 104 \%

For this reaction, the percent yield is 104%

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Oduvanchick [21]

Answer:

28.75211 kj

Explanation:

Given data:

Mass of iron bar = 841 g

Initial temperature = 84°C

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Heat released = ?

Solution:

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It is the amount of heat required to raise the temperature of one gram of substance by one degree.

specific heat capacity of iron is 0.444 j/g.°C

Formula:

Q = m.c. ΔT

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m = mass of given substance

c = specific heat capacity of substance

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By putting values,

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If you place 5 moles of sodium chloride and 4 moles of sucrose into 11 moles of water, the Mole fraction of sodium chloride would be 0.25.  The mole fraction is equal to the moles of a substance divided by the total number of moles.

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