Answer:
75.47
Explanation:
AS WE CANT WEIGHT AIR THE ANSWER IS CORRECT
Answer:
The correct answer is option d.
Explanation:
On submission of an incorrect answer to a multiple-choice question with n options, we will lose:
of credit
If we multiple-choice question has five answer choices. And we have submitted 1 wrong answer. the fraction of credit we loose :
of credit
of credit
credit
The percentage of credit we loose:
of credits
of credits
Answer:
Explanation:
Cu(NO₃)₂ + 4NH₃ = Cu(NH₃)₄²⁺ + 2 NO₃⁻
187.5 gm 4M 1 M
187.5 gm reacts with 4 M ammonia
18.8 g reacts with .4 M ammonia
ammonia remaining left after reaction
= .8 M - .4 M = .4 M .
187.5 gm reacts with 4 M ammonia to form 1 M Cu(NH₃)₄²⁺
18.8 g reacts with .4 M ammonia to form 0.1 M Cu(NH₃)₄²⁺
At equilibrium , the concentration of Cu²⁺ will be zero .
concentration of ammonia will be .4 M
concentration of Cu(NH₃)₄²⁺ formed will be 0.1 M
Answer:
Explanation:
Hello there!
In this case, since the combustion of butane is:
Thus, since the molar mass of butane is 58.12 g/mol and that of carbon dioxide is 44.01 g/mol, we obtain the following mass of CO2 product:
Best regards!
Answer:
1672 J
Explanation:
We are supposed to find out the energy released by water when cooled from 50° C to 30°C .
We have the relation that ,
H=msΔT
Information is given that s=4.18 J/ g*°C ,
m=20.0 g,
and ΔT is -20° C.
Hence by substituting we get,
H=-20*20*4.18
(minus symbol represents that energy is being released)
1672 J is release when water is cooled from 50° C to 30°C .
