Answer:
Part 1) ![sin(B)=\frac{21}{29}](https://tex.z-dn.net/?f=sin%28B%29%3D%5Cfrac%7B21%7D%7B29%7D)
Part 2) ![csc(A)=\frac{29}{20}](https://tex.z-dn.net/?f=csc%28A%29%3D%5Cfrac%7B29%7D%7B20%7D)
Part 3) ![cot(A)=\frac{21}{20}](https://tex.z-dn.net/?f=cot%28A%29%3D%5Cfrac%7B21%7D%7B20%7D)
Step-by-step explanation:
<u><em>The complete question is</em></u>
Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B
The picture of the question in the attached figure
Part 1) Write the ratio equivalent to: Sin B
we know that
In the right triangle ABC
----> by SOH (opposite side divided by the hypotenuse)
substitute the values
![sin(B)=\frac{21}{29}](https://tex.z-dn.net/?f=sin%28B%29%3D%5Cfrac%7B21%7D%7B29%7D)
Part 2) Write the ratio equivalent to: Csc A
we know that
In the right triangle ABC
![csc(A)=\frac{1}{sin(A)}](https://tex.z-dn.net/?f=csc%28A%29%3D%5Cfrac%7B1%7D%7Bsin%28A%29%7D)
-----> by SOH (opposite side divided by the hypotenuse)
substitute the values
![sin(A)=\frac{20}{29}](https://tex.z-dn.net/?f=sin%28A%29%3D%5Cfrac%7B20%7D%7B29%7D)
therefore
![csc(A)=\frac{29}{20}](https://tex.z-dn.net/?f=csc%28A%29%3D%5Cfrac%7B29%7D%7B20%7D)
Part 3) Write the ratio equivalent to: Cot A
we know that
In the right triangle ABC
![cot(A)=\frac{1}{tan(A)}](https://tex.z-dn.net/?f=cot%28A%29%3D%5Cfrac%7B1%7D%7Btan%28A%29%7D)
-----> by TOA (opposite side divided by the adjacent side)
substitute the values
![tan(A)=\frac{20}{21}](https://tex.z-dn.net/?f=tan%28A%29%3D%5Cfrac%7B20%7D%7B21%7D)
therefore
![cot(A)=\frac{21}{20}](https://tex.z-dn.net/?f=cot%28A%29%3D%5Cfrac%7B21%7D%7B20%7D)
A: 2,5
B: 3,1
C: -2,4
Explanation:
When you’re moving right and up you would add however many numbers you moved up to the original points because going right on a graph makes the X a larger number, and going up makes it larger.
F(x) = 2x² - 8x - 10.
This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:
a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex
b) for x = 2, f(x) = f(2) = - 18 (component of y of the vertex)
c) VERTEX(2, - 18)
d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144
Answer: it’s C
Because Kendall scored 3 times abdul
Janes weight = x
Twelve pounds less than twice janes weight is 270 pounds
12 less than 2x is 270
2x -12 = 270 (add 12 to each side)
2x = 270 + 12
2x = 282 (divide 2 from each side)
x = 282/2
x = 141
The answer is 141 pounds