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2 years ago

Slightly fraction that is equivalent to 2/3

Mathematics

2 answers:

pychu [463]2 years ago

8 0

Answer:

12/18

Step-by-step explanation:

blondinia [14]2 years ago

8 0

Answer:4/6

Step-by-step explanation:

You might be interested in

X - y= -4 -2x +3y =6

STatiana [176]

Answer:

x=-6, y=-2, (As a point) (-6, -2).....The point form is not necessary unless you want to solve the system (of equations) by graphing.

Step-by-step explanation:

By substitution:

x-y=-4 By adding y on both sides,

x=y-4

Now you can substitute x for the expression (y-4)

Plug the (y-4) as x in the other equation.

So -2x+3y=6 becomes

-2(y-4)+3y=6

Now solve:

-2(y-4)+3y=6 distributes out to be

-2y+8+3y=6 Now combining like terms

y+8=6 Subtract 8 on both sides to isolate the variable

y=-2

Now plug the value -2 in where the y is in any equation (preferably the easier/less complicated one) and solve for x.

So x-y=-4 becomes

x-(-2)=-4

=x+2=-4

=x=-6

3 0

3 years ago

Find the measures of two angles, one positive and one negative, that are coterminal with the given angle. 240°

Olin [163]

One would be 240 + 360 = 600 degrees
and negative = 240-360 = -120 degrees

4 0

3 years ago

Read 2 more answers

I need some help with math

Irina18 [472]

Answer:

$(y-7)^2+(x-2)^2=16$

and

$(x+2)^2+(y-15)^2 = 9$

Step-by-step explanation:

The standard equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where the coordinate (h,k) is the center of the circle.

Second Problem:

We can start with the second problem which uses this info very easily.
(h,k) in this problem is (-2,15) simply plug these into the equation. $(x--2)^2+(y-15)^2=r^2$ .
We can also add the radius 3 and square it so it becomes 9. The equation.
This simplifies to $(x+2)^2+(y-15)^2 = 9$ .

First Problem:

The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
$y^2-14y+x^2-4x+37=0$ first subtract 37 from both sides so the equation is now $y^2-14y+x^2-4x=-37$ .
$y^2-14y+x^2-4x+37=0$ by adding $(-\frac{b}{2a} )^2$ to both the x and y portions of this equation you can complete the squares. $(-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2$ and $(-\frac{-4}{2(1)})^2$ which equals 49 and 4.
Add 49 and 4 to both sides and the equation is now: $y^2-14y+49+x^2-4x+4=-37+49+4$ You can simplify the y and x portions of the equations into the perfect squares or factored form $(y-7)^2$ and $(x-2)^2$ .
Finally put the whole thing together. $(y-7)^2+(x-2)^2=16$ .