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Vlad1618 [11]
3 years ago
5

A projectile is fired into the air, and it follows the parabolic path shown in the drawing, landing on the right. there is no ai

r resistance. at any instant, the projectile has a velocity v overscript rightwards harpoon with barb upwards endscripts and an acceleration a overscript rightwards harpoon with barb upwards endscripts. which one or more of the drawings could not represent the directions for v overscript rightwards harpoon with barb upwards endscripts and a overscript rightwards harpoon with barb upwards endscripts at any point on the trajectory?
Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

Answer : Neither option A nor option C could represent the directions for v overscript rightwards harpoon with barb upwards endscripts and a overscript rightwards harpoon with barb upwards endscripts at any point on the trajectory.

As the acceleration is always downward, and also in this question the only force acting is the projectiles weight. Therefore, it is experiencing downward acceleration at  any point of time.

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The farmers wife baked 9 pies on Monday and 5 on Tuesday. How many more pies did she bake on Monday?
insens350 [35]

Answer:

4

Step-by-step explanation:

9 - 5 = 4

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SOLVE THIS PLS JSJSXHHX
madam [21]

Step-by-step explanation:

y = ax + b

I see already the result (y = x/10 × 1/6), but let's go in formally.

we have multiple function points to use to officially calculate a and b.

1/6 = a×10 + b

2/3 = a×40 + b

5/6 = a×50 + b

1 2/3 = a×100 + b

let's e.g subtract equation 1 from equation 3.

4/6 = a×40 + 0

a = 4/40 / 6 = 4 / 240 = 1/60

1/6 = 10/60 + b

1/6 = 1/6 + b

b = 0

so, the function is

y = x/60

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3 years ago
What does 8-2(y+4)=1/2(8y-12) equal?
JulsSmile [24]

y = 1

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3 years ago
Read 2 more answers
What is the shape of the graph of the function?<br> g(x)= 3/2 (2/3) ^x
Andrew [12]

Answer:

Please check the attached graph.

From the graph, it is clear that option B is the correct option.

Step-by-step explanation:

Given the function

g\left(x\right)=\:\frac{3}{2}\:\left(\frac{2}{3}\right)^x

Determining the y-intercept

We know that the value of the y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

so

substituting x = 0 in the fuction

y=\:\frac{3}{2}\:\left(\frac{2}{3}\right)^x

y=\:\frac{3}{2}\:\left(\frac{2}{3}\right)^0

Apply rule:  a^0=1,\:a\ne \:0

y=1\cdot \frac{3}{2}

y=\frac{3}{2}

y = 1.5

Therefore, the point representing the y-intercept is:

  • (0, 1.5)

Determining the x-intercept

We know that the value of the x-intercept can be determined by setting y = 0, and determining the corresponding value of x.

so

substituting y = 0 in the function

0=\frac{3}{2}\left(\frac{2}{3}\right)^x

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

\left(\frac{2}{3}\right)^x=0

We know that a^{f\left(x\right)} can not be zero or negative for x ∈ R

Thus, NONE represents the x-intercept.

Please check the attached graph.

From the graph, it is clear that option B is the correct option.

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Explain how to calculate the radius of a<br> circle if you know its diameter.
Marianna [84]

Answer:

r=d÷2 is the right answer

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