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3 years ago

12

What is the absolute value of the integer –12

1 answer:

8090 [49]3 years ago

3 0

The absolute value would be written as |-12|. The absolute value of a negative number is results in a positive number. The answer is 12.

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Answer

$y = 28 \sin(\frac{\pi}{6} - \frac{2\pi}{3}) + 49$

Step by Step Explanation

Given

See attachment for table

Required

Determine the sinusoidal function

The sinusoidal function is represented as:

$y = A \sin(Bx + C) + D$

Where

$|A| = Amplitude$

And it is calculated as:

$A = \frac{1}{2}[Highest - Least]$

From the table:

Highest = 77 and Least = 21

So:

$A = \frac{1}{2}[77 - 21]$

$A = \frac{1}{2}[56]$

$A = 28$

B is calculated as:

$Period = \frac{2\pi}{B}$

The period is 12 i.e. 12 months

So:

$\frac{2\pi}{B} = 12$

$B = \frac{2\pi}{12}$

$B = \frac{\pi}{6}$

C is calculated as:

$\frac{C}{B} = -4$

$C = -4 * B$

$C = -4 * \frac{\pi}{6}$

$C = -2 * \frac{\pi}{3}$

$C = -\frac{2\pi}{3}$

Lastly, D is calculated as:

$D = Least + A$

So:

$D =21 + 28$

$D=49$

So, the function is:

$y = A \sin(Bx + C) + D$

$y = 28 \sin(\frac{\pi}{6} - \frac{2\pi}{3}) + 49$

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