Answer:
a. P(male) = 0.4
b. P(no sport and male) = 0.1
c. Unclear question (isn't it the same as b.?)
Step-by-step explanation:
The data below is what I've worked according to, which isn't very clear from the question so the answers are only correct if this is the correct table of data;
![\left[\begin{array}{ccc}&No \ Sports&Sports\\Female&10&32\\Male&7&21\end {array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%26No%20%5C%20Sports%26Sports%5C%5CFemale%2610%2632%5C%5CMale%267%2621%5Cend%20%7Barray%7D%5Cright%5D)
a.
b.
Using the tree diagram in the picture;
Answer:
a(8a-1)(3a+5)
Step-by-step explanation:
24a³ + 37a² – 5a =
a ( 24a²+ 37a -5) =
a( 24a² +40a -3a -5) =
a [8a(3a+5) -1(3a+5) ]=
a(8a-1)(3a+5)
Answer:c
Step-by-step explanation:i tookthe test
9514 1404 393
Answer:
100°
Step-by-step explanation:
The relevant relation for angle x is ...
x = (AB +DE)/2
and for angle y, it is ...
y =(AC -DE)/2
Using the second relation to write an expression for DE, we have ...
DE = AC -2y
In the first equation, this lets us write ...
x = (AB +(AC -2y))/2 = (AB +(2AB -2y))/2
2x = 3AB-2y . . . . . . . . . . . . . . multiply by 2
(2x +2y)/3 = AB = AC/2 . . . . . add 2y; divide by 3
AC = (4/3)(x +y) = (4/3)(60° +15°) . . . . multiply by 2, substitute known values
AC = 100°
