Answer:
![y= \frac{3}{4} x+\frac{75}{2}](https://tex.z-dn.net/?f=y%3D%20%5Cfrac%7B3%7D%7B4%7D%20x%2B%5Cfrac%7B75%7D%7B2%7D)
Step-by-step explanation:
Answer: x < 4
Step-by-step explanation:
So, let's look at the problem:
|x + 7| < 11
We want to get rid of extra numbers, so lets get rid of that seven my subtracting it! But make sure you do the same thing on both sides!
x < 4
Your answer would be four! Hope I helped! <3
Answer:
2:4
Step-by-step explanation:
Answer:
x = 1
Step-by-step explanation:
<u>FACTS TO KNOW BEFORE SOLVING :-</u>
Lets say , there's an expression → ![a = b^c](https://tex.z-dn.net/?f=a%20%3D%20b%5Ec)
In terms of logarithm , it can be written as → ![\log_b a = c](https://tex.z-dn.net/?f=%5Clog_b%20a%20%3D%20c)
<u>SOLUTION :-</u>
![\log_{64}8 = \frac{x}{2}](https://tex.z-dn.net/?f=%5Clog_%7B64%7D8%20%3D%20%5Cfrac%7Bx%7D%7B2%7D)
It can be also written as -
![64^{\frac{x}{2} }= 8](https://tex.z-dn.net/?f=64%5E%7B%5Cfrac%7Bx%7D%7B2%7D%20%7D%3D%208)
In L.H.S. , 64 can be written as 8² and in R.H.S. , 8 can be written as 8¹. So,
![=> 8^{(\frac{x}{2} \times 2)} = 8^1](https://tex.z-dn.net/?f=%3D%3E%208%5E%7B%28%5Cfrac%7Bx%7D%7B2%7D%20%5Ctimes%202%29%7D%20%3D%208%5E1)
![=> 8^x = 8^1](https://tex.z-dn.net/?f=%3D%3E%208%5Ex%20%3D%208%5E1)
According to the law of exponents , the bases are equal in L.H.S & R.H.S. .So, their exponents in L.H.S. & R.H.S. must be equal.
![=> x = 1](https://tex.z-dn.net/?f=%3D%3E%20x%20%3D%201)
Answer:
4 a.m on Wednesday
Step-by-step explanation:
The correct answer on Edg..