Ask question

Ask question

All categories

2 years ago

8

Russell randomly surveys seventh graders in his schools and finds 6 of 30 attend summer camp. if there are 200 seventh graders i

n his school, about how many are expected to attend summer camp.

2 answers:

suter [353]2 years ago

7 0

The answer is 40 EXPLANATION: 6% of 30 is 20%. 20% of 200 is 40

Lena [83]2 years ago

4 0

Answer:

40

Step-by-step explanation:

You might be interested in

The tables below show four sets of data:

artcher [175]

Answer:

are think my answer is A, because x and y are are the same

6 0

2 years ago

Write each of the following decimals in words.

Sergeeva-Olga [200]

A. nine hundredths

B. Thirty five hundredths

C. Seven Tenths

D. Three Thousandths

E. One Hundred Fourty five Thousandths

F. Fifty Nine Ten Thousandths

8 0

2 years ago

(PLEASE HELP) (NO SPAM) Complete the special right tringale:

marusya05 [52]

Answer:

Step-by-step explanation:

BD is opposite the 30° angle. The sine of 30° is 0.5. The sin of an angle in a right triangle is opposite/hypotenuse so BD = sin 30°x8.

Now you have two known lengths The third can be found by applying the Pythagorean theorem: BC²+BD²=CD², from which you can establish a numerical value for BC.

6 0

2 years ago

Solve the problem. The half-life of plutonium-234 is 9 hours. If 50 milligrams is present now, how much will be present in 6 day

MaRussiya [10]

Answer:

4) 0.001

Step-by-step explanation:

The amount (a) present in h hours is ...

a(h) = (initial value)×(1/2)^(h/(half-life))

6 days is 6×24 hours, so the amount remaining is ...

a(6×24) = 50×(1/2)^(6×24/9) = 50/2^16 ≈ 0.001 . . . . milligrams

3 0

2 years ago

In a newspaper poll concerning violence on television, 589 people were asked, "What is your opinion of the amount of violence on

abruzzese [7]

Answer:

(a) $P(Y'|M)\approx 0.3297$

(b) $P(Y|M')\approx 0.8323$

(c) $P(Y'|M')\approx 0.1323$

Step-by-step explanation:

Given table is

Yes No Don't Know Total

Men 162 92 25 279

Women 258 41 11 310

Total 420 133 36 589

According the the conditional probability, if A and B are two event then

$P(A|B)=P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}$

We need to find the following probabilities.

Let Y is the event "saying yes," and M is the event "being a man."

(a)

$P(Y'|M)=\frac{P(Y'\cap M)}{P(M)}$

$P(Y'|M)=\frac{\frac{92}{589}}{\frac{279}{589}}$

$P(Y'|M)=\frac{92}{279}$

$P(Y'|M)=0.329749103943$

$P(Y'|M)\approx 0.3297$

(b)

$P(Y|M')=\frac{P(Y\cap M')}{P(M')}$

$P(Y|M')=\frac{\frac{258}{589}}{\frac{310}{589}}$

$P(Y|M')=\frac{258}{310}$

$P(Y|M')=0.832258064516$

$P(Y|M')\approx 0.8323$

(c)

$P(Y'|M')=\frac{P(Y'\cap M')}{P(M')}$

$P(Y'|M')=\frac{\frac{41}{589}}{\frac{310}{589}}$

$P(Y'|M')=\frac{41}{310}$

$P(Y'|M')=0.132258064516$

$P(Y'|M')\approx 0.1323$

5 0

2 years ago