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Marina86 [1]
3 years ago
5

5% of adults participate in at least 30 minutes of exercise each day. How likely is it that a randomly chosen adult will exercis

e 30 minutes each day?
Mathematics
1 answer:
MaRussiya [10]3 years ago
6 0

Answer:

5 out of 100 adults so not very likely

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HELP MEEEE PLEASEEEEEEEEEEEEEE
Agata [3.3K]

Answer:

a = 4

Step-by-step explanation:

a^2 + b^2 = c^2

a= ?

b= 3

c= 5 (c is always the hypotenuse)

*plug in given values

a^2 + 3^2 = 5^2

a^2 + 9 = 25

-9 -9

a^2 = 16

*find the square root

sqrt(a) = sqrt(16)

a = 4

8 0
3 years ago
Read 2 more answers
What is the solution to the equation −p − 13 = −4 /3 p + 2/3 ( 5p − 6 ) ?
jekas [21]

Answer:

The answer is p= 2 and 1/3

Step-by-step explanation:

This answer can be found using the order of operations to solve for p.

Start by distributing 2/3 by (5p-6)

add -4/3p to 10/3p equaling 6/3p or 2p

subtract 13 from both sides

-p= 2p - 7

p=2 and 1/3

3 0
2 years ago
With a little care, you can find the median and the quartiles from the histogram. what are these numbers? you can also find the
coldgirl [10]

Complete Question

The histogram from this question is shown on the first uploaded image

Answer:

The first quartile is  1st Q = 19^{th} girl (subject ) = 1 \serving\ of\ fruit\ per\ day

The median is   Median  = 38 ^{th} \ girl (subject) =  2 \serving\ of\ fruit\ per\ day

The third quartile  is 3rd Q =  56^{th} \  girl (subject) = 4 \serving\ of\ fruit\ per\ day  

The  mean is  \= x = 2.62

Step-by-step explanation:

From the question we are told that

   The total  number of girls is n =  74

Generally the median is mathematically represented as

       Median  =  \frac{\frac{n}{2}  +[ \frac{n}{2} + 1]  }{2}

So

          Median  =  \frac{\frac{74}{2}  +[ \frac{74}{2} + 1]  }{2}

=>         Median  =  \frac{37  +38 }{2}

=>         Median  =37.5 \  girl    

From the histogram 37.5 \approx 38^{th} \ girl fall under 2 fruits per day

Generally the first quartile is mathematically represented as

      1st \ Q =  \frac{\frac{n}{4} + [\frac{n}{4} + 1]  }{2}

=>    1st \ Q =  \frac{\frac{74}{4} + [\frac{74}{4} + 1]  }{2}

=>     1st \ Q = 19 \  girl

From the histogram 19^{th}girl fall under 1 fruit per day

 Generally the third quartile is mathematically represented as

     3rd\  Q =  \frac{\frac{n}{2}  + n }{2}

=>    3rd\  Q =  \frac{\frac{74}{2}  + 74 }{2}

=>    3rd\  Q =  55.5

From the histogram 55.5 \approx 56^{th} \ girl fall under 4 fruits per day

Generally from the histogram table the frequency  [number of subjects (girls) ]  and the servings of fruit per day can be represented as

                                                                                                               Total

x(servings per day )        0     1     2     3     4     5    6     7      8    

f (number of subjects )   15    11   15     11    8     5    3     3      3    \sum f  =  74

xf                                       0    11    30   33   32  25   18   21     24    \sum xf =  194

Generally the mean is mathematically represented as

      \= x = \frac{1}{ \sum f}  * [\sum xf]

=>     \= x = \frac{1}{ 74}  *194

=>      \= x = 2.62

4 0
3 years ago
Gandalf the grey started in the forest of mirkwood at a point pp with coordinates (−2,1)(−2,1) and arrived in the iron hills at
AlladinOne [14]
Travel direction 3i + 2j, slope = 2/3.
We have slope and a point (-2,1) this gives us a line equation:
 LINE BEFORE THE TURN, EQUATION: y = (2/3)x + 1

The point of intersection of the two lines:
1) through (-2,1) with slope 2/3 and;
2) through (-1,6) with slope 3/2. 
8 0
3 years ago
What is the rate of change between (2,2) and (17,7)
choli [55]

Answer:

1/3

Step-by-step explanation:

(7-2)/(17-2)=5/15=1/3

5 0
3 years ago
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