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SIZIF [17.4K]
3 years ago
5

How many 3/8's are in 6?

Mathematics
2 answers:
GrogVix [38]3 years ago
8 0

Answer:

That is 6 divided by 3/8, better written as

6

--

1

====

3

--

8

Invert the 3/8 and then multiply:

6      8

-- *   ---

1       3

Reduce 6/3:  6/3 = 2

Then you have 2(8), or 16 (answer)

densk [106]3 years ago
3 0

Answer:

There are 16 3/8's  in 6

Step-by-step explanation:

6/1 divided by 3/8

Invert the 3/8 and then multiply

6/1 times 8/3

Reduce 6/3:  6/3 = 2

answer: 16

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The power generation plant of a ship is outfitted with two identical diesel-generator sets. One single set running stand-alone c
dem82 [27]

Answer:

probability of an electric power outage shipboard is 0.075 or 7.5 %

Step-by-step explanation:

Given the data in the question;

Probability of engine malfunction = 25% = 0.25

Probability of generator malfunction = 10% = 0.1  

Probability of generator being repaired = 50% = 0.5

probability of an electric power outage shipboard = ?

To get the probability of an electric power outage shipboard, we use the expression;

probability of an electric power outage = 2_c_1 × p( Probability of generator malfunction ) × p( Probability of generator being repaired ) × ( 1 - p( Probability of engine malfunction ) )

so we substitute in our given values;

probability of an electric power outage = 2 × 0.1 × 0.5 × ( 1 - 0.25 )

probability of an electric power outage = 2 × 0.1 × 0.5 × 0.75

probability of an electric power outage = 0.075 or 7.5 %

3 0
3 years ago
In the proportion 2:3 = 16:24 ,the product of the two middle values is __.
klio [65]

Answer:

48 and 48

Step-by-step explanation:

product means multiplication

two middle values are 3 and 16

3*16 = 48

two outside values are 2 and 24

2*24 = 48

4 0
3 years ago
In rectangle PQRS, PR = 18x – 28 and QS = x + 380. Find the value of x and the length of each diagonal.
Flauer [41]

Diagonals of a rectangle are congruent.


18x - 28 = x + 380


Solving for x, I get 17.


So, x = 17.


PR = 18x - 28


PR = 18(17) - 28


PR = 278


QS = x + 380


QS = 17 + 380


QS = 397

5 0
3 years ago
Read 2 more answers
I need some help. Please
Ilya [14]

Are you able to ask your teacher?

7 0
3 years ago
A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6
katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is 49\ ft

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

h(t)=-16t^{2} +63t+4

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

h(3)=-16(3)^{2} +63(3)+4=49\ ft

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

so

Convert the function into a vertex form

h(t)=-16t^{2} +63t+4

Group terms that contain the same variable, and move the constant to the opposite side of the equation

h(t)-4=-16t^{2} +63t

Factor the leading coefficient

h(t)-4=-16(t^{2} -(63/16)t)

Complete the square. Remember to balance the equation by adding the same constants to each side

h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})

h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})

Rewrite as perfect squares

h(t)-(67,600/1,024)=-16(t-(63/32))^{2}

h(t)=-16(t-(63/32))^{2}+(67,600/1,024)

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

so

h(t)=-16t^{2} +63t+4

For h(t)=0

0=-16t^{2} +63t+4

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0
3 years ago
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