find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length
To find the perimeter of a triangle we add all the sides of the triangle
The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches
Perimeter of a triangle =
15 inches + 15 inches + 21 inches = 51 inches
So 51 inches is the perimeter
Answer:
see explanation
Step-by-step explanation:
In a rectangle
• All angles are right angles
• the diagonals are congruent
In Δ WXV the sum of the 3 angles = 180°
∠ WXZ = ∠ XWY =
=
= 58°
∠ YXZ = 90° - 58° = 32°
∠ WVZ = 180° - 64° = 116° ( adjacent angles are supplementary )
∠ XWZ = 90° ( by definition of rectangle )
∠ XZY = ∠ WXZ = 58° ( corresponding angles )
Answer:
(7y + 3x)(7y - 3x)
Step-by-step explanation:
a² - b² = (a + b)(a - b)
49y² - 9x² = (7y)² - (3x)² {a = 7y ; b - 3x}
= (7y + 3x)(7y - 3x)
Answer:
20
Step-by-step explanation:
5 divided by 100 = 20