Use the Product Rule: x^ax^b = x^a + b
6x^3 + 1y^2 + 6
Simplify 3 + 1 to 4
6x^4y^2 + 6
Simplify 2 + 6 to 8
<u>= C) 6x^4 y^8</u>
To find the cost of each book, you need to divide the money spent on all of the books by the number of books.
$39 / 10 = $3.90 per book
Answer:


Step-by-step explanation:
Given

Required
Find all product of real values that satisfy the equation

Cross multiply:


Subtract 7 from both sides


Reorder

Multiply through by -1

The above represents a quadratic equation and as such could take either of the following conditions.
(1) No real roots:
This possibility does not apply in this case as such, would not be considered.
(2) One real root
This is true if

For a quadratic equation

By comparison with 



Substitute these values in 


Add 56 to both sides


Divide through by 4

Take square roots


Hence, the possible values of r are:
or 
and the product is:


Answer:
Step-by-step explanation:
A comparison between a function and its inverse would show that the domain and range of the original function swap. The domain of the function becomes the range of the inverse, the range of the function becomes the domain of its inverse.
Looking at ordered pairs of the function and its inverse would look like this:
(2,4) on the original function becomes (4,2) on the inverse.
While the graph of a function and its inverse are noticeably different an important thing to note is that it is merely a reflection across the line y=x.
So even though they appear different you are looking at the same relationship just as y vs. x instead of x vs. y
I hope this helped you because i barley understood this myself.
Read more on Brainly.com - brainly.com/question/2834818#readmore