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Anon25 [30]
3 years ago
7

Solve for x round to the nearest tenth.

Mathematics
1 answer:
tester [92]3 years ago
6 0

Answer:

yo moma

Step-by-step explanation:

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bigger

Step-by-step explanation:

-3 is bigger then -12

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A, B, & D

Step-by-step explanation:

Because they all have equal signs

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Which value of a would make the expression 5 1/3 divided by 4/a equivalent to a whole number?
Leya [2.2K]

9514 1404 393

Answer:

  a = any positive multiple of 3

Step-by-step explanation:

You want ...

  (5 1/3)/(4/a) = whole number

  (16/3)·(a/4) = whole number

  (4a/3) = whole number

This will be the case for a = 3n, for any positive integer n.

8 0
2 years ago
During halftime of a basketball ​game, a sling shot launches​ T-shirts at the crowd. A​ T-shirt is launched from a height of 4 f
Sonbull [250]

Answer:

(a) The time the T-shirt takes to maximum height is 2 seconds

(b) The maximum height is 68 ft

(c) The range of the function that models the height of the T-shirt over time given above is 4 + 64\cdot t - 16 \cdot  t^{2}

Step-by-step explanation:

Here, we note that the general equation representing the height of the T-shirt as a function of time is

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

Where:

h = Height reached by T-shirt

t = Time of flight

u = Initial velocity = 64 ft/s

g = Acceleration due to gravity (negative because upward against gravity) = 32 ft/s²

h₁ = Initial height of T-shirt = 4 ft

(a) The maximum height can be found from the time to maximum height given as

v = u - gt

Where:

u = Initial velocity = 64 ft/s

v = Final upward velocity at maximum height = 0 m/s

g = 32 ft/s²

Therefore,

0 = 64 - 32·t

32·t = 64 and

t = 64/32 = 2 seconds

(b) Therefore, maximum height is then

h = 4 + 64\times 2 - \frac{1}{2} \times 32  \times  2^{2}

∴ h = 68 ft

The T-shirt is then caught 41 ft above the court on its way down

(c) The range of the function that models the height of the T-shirt over time given above is derived as

h = h_1 + u\cdot t - \frac{1}{2} \cdot g  \cdot  t^{2}

With u = 64 ft/s

g = 32 ft/s² and

h₁ = 4 ft

The equation becomes

h =4 + 64\cdot t - \frac{1}{2} \times 32  \cdot  t^{2} = 4 + 64\cdot t - 16 \cdot  t^{2}.

6 0
3 years ago
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