PLEASE ZOMEONE HELP

Nikolay [14]

Its D because the number shaded is 6 and circles 8 that is 6/8 and decimal vesion 0.75 in D there was 3/4 its 0.75 so D is your answer

5 0

3 years ago

Ema had 2/8 of a cookie, she wanted to share the rest of it equally with her friend; how many pieces will each friend get?

Nostrana [21]

Answer:0.125 or 1/8

Step-by-step explanation:

7 0

3 years ago

The table showing the stock price changes for a sample of 12 companies on a day is contained in the Excel file below.

AfilCa [17]

Answer:

(a) The sample variance for the daily price change is 0.2501.

(b) The sample standard deviation for the daily price change is 0.5001.

(c) The 95% confidence interval estimates of the population variance is (0.1255, 0.7210).

Step-by-step explanation:

Let the random variable X denote the stock price changes for a sample of 12 companies on a day.

The data provided is:

X = {0.82 , 1.44 , -0.07 , 0.41 , 0.21 , 1.33 , 0.97 , 0.30 , 0.14 , 0.12 , 0.42 , 0.15}

(a)

The formula to compute the sample variance for the daily price change is:

$s^{2}=\frac{1}{n-1}\sum\limits^{12}_{i=1}{(X_{i}-\bar X)^{2}}$

The sample mean is computed using the formula:

$\bar X=\frac{1}{n}\sum\limits^{12}_{i=1}{X_{i}}$

Consider the Excel output attached below.

In Excel the formula to compute the sample mean and sample variance are:

$\bar X$ =AVERAGE(A2:A13)

$s^{2}$ =VAR.S(A2:A13)

Thus, the sample variance for the daily price change is 0.2501.

(b)

The formula to compute the sample standard deviation for the daily price change is:

$s=\sqrt{\frac{1}{n-1}\sum\limits^{12}_{i=1}{(X_{i}-\bar X)^{2}}}$

Consider the Excel output attached below.

In Excel the formula to compute the sample standard deviation is:

$s$ =STDEV.S(A2:A13)

Thus, the sample standard deviation for the daily price change is 0.5001.

(c)

The (1 - α)% confidence interval for population variance is:

$CI=[\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2} } \leq \sigma^{2}\leq \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2} } ]$

Compute the critical value of Chi-square for α = 0.05 and (n - 1) = (12 - 1) = 11 degrees of freedom as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2,11}=21.920$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{(1-0.05/2),11}=\chi^{2}_{0.975,11}=3.816$

*Use a Chi-square table.

Compute the 95% confidence interval estimates of the population variance as follows:

$CI=[\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2} } \leq \sigma^{2}\leq \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2} } ]$

$=[\frac{(12-1)\times 0.2501}{21.920 } \leq \sigma^{2}\leq \frac{(12-1)\times 0.2501}{3.816} ]$

$=[0.125506\leq \sigma^{2}\leq 0.720938]\\\approx [0.1255, 0.7210]$

Thus, the 95% confidence interval estimates of the population variance is (0.1255, 0.7210).

7 0

4 years ago

Which translation maps the graph of the function f(x) equals X to add to the function GX equals X2 onto the function g(x) = x2 +

NNADVOKAT [17]

Answer:

left 1 unit, up 5 units

Step-by-step explanation:

To answer the question:

Which translation maps the graph of the function f(x) = x² onto the function g(x) = x² + 2x + 6?

we need to find the vertex of g(x), as follows:

x-coordinate of the vertex (h): -b/(2a) = -2/(2*1) = -1

y-coordinate of the vertex (k): y = (-1)² + 2(-1) + 6 = 5

Therefore, g(x) can be rewritten as:

g(x) = a(x - h)² + k

g(x) = (x + 1)² + 5

which is the equation of f(x) = x² translated 1 unit to the left and 5 units up.

5 0

3 years ago

sharon and anthony dropped a stone from a 150-foot cliff. find the time, t, in seconds that it will take for the stone to reach

shutvik [7]

Work:
(s = 150ft
t = 1/4 square root of s)
Square Root (150) = 12.2474487139
12.2474487139 ÷ 4 = 3.0618621785 = ~3.062

Final Answer: About 3.062 seconds.

7 0

3 years ago