1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².
a = 51 m, b = 37 m, c = 20 m
semiperimeter: p = (51+37+20):2 = 54 m
Area of triangle:
Rate: ₹ 3 per m².
Cost: ₹ 3•306 = ₹ 918
2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.
a = 5 cm
a+2b = 11 cm ⇒ 2b = 6 cm ⇒ b = 3 cm
p = 11:2 = 5.5
3. Find the area of the equilateral triangle whose each side is 8 cm.
a = b = c = 8 cm
p = (8•3):2 = 12 cm
4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.
a = 2x
b = 3x
2x + 2•3x = 32 cm ⇒ 8x = 32 cm ⇒ x = 4 cm ⇒ a = 8 cm, b = 12 cm
p = 32:2 = 16 cm
Answer:
I think it would be -1 its hard to explain but I am very positive
Step-by-step explanation:
Answer:
u 2
and stay positive :)
Step-by-step explanation:
Answer:
y = -1/3x + 2
Step-by-step explanation:
The gradient of the given line is 3 because (y = mx +c where m is the gradient)
Therefore, to find the gradient of the perpendicular line (at 90 degrees), you need to find the negative reciprocal.
The negative reciprocal of 3 is -1/3 because imagine if 3 = 3/1, to get the reciprocal, you flip it, and to get the negative, you just flip the sign.
Now we know that Line M is y = -1/3x + c, we need to find the y-intercept.
To do this, just input the point (3,1) into y = -1/3x + c, to get c. This is because we know (3,1) is on the line from the question.
So it would be 1 = (-1/3 x 3) +c
Which would be 1 = -1 +c
And so c = 2
Put everything together and you get y = -1/3x + 2
