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Goshia [24]
3 years ago
9

Can i get some help with this?

Mathematics
1 answer:
liberstina [14]3 years ago
7 0

Answer:

Look at the image, pls give brainliest!

Step-by-step explanation:

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How to solve 6p^2-42p-48
Vlad1618 [11]
What are you trying to solve?

7 0
3 years ago
Read 2 more answers
GEW has angle measures given by m/_G=5x + 66, m?/_ E = 3x, and m/_ W= 142 -4x whats the mesure of e
8090 [49]

Answer:

21°

Step-by-step explanation:

GEW has angle measures given by m/_G=5x + 66, m?/_ E = 3x, and m/_ W= 142 -4x whats the mesure of e

= 5x + 66 + 3x + 142 - 4x = 180

4x + 208 = 180

4x = 208 - 180

4x = 28

x = 28/4

x = 7

Solving for E = 3x

E = 3 × 7

E = 21°

7 0
3 years ago
How are percent transmittance and absorbance related algebraically?
statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:  


A ∝ b · c

As Transmittance, T =\dfrac{P}{P_0}

% Transmittance, \%T=100\times T

Absorbance,

A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T

Hence, A=\log_{10}\times \dfrac{1}{T} is the algebraic relation between absorbance and transmittance.


8 0
3 years ago
the vertex of this parabola is at (3,5). When the y-value is 6, the x-value is -1. What is the coefficient of the squared term i
otez555 [7]
Now, assuming is a vertical parabola, so the squared variable is the "x", let's do some checking.

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=3\\
k=5
\end{cases}\implies y=a(x-3)^2+5
\\\\\\
\textit{we also know that }
\begin{cases}
y=6\\
x=-1
\end{cases}\implies 6=a(-1-3)^2+5
\\\\\\
1=a(-4)^2\implies 1=16a\implies \cfrac{1}{16}=a
6 0
3 years ago
Find the unit rate. Round to the nearest hundredth, if necessary. $120 for 18 ft2
erik [133]

Answer:

no

Step-by-step explanation:

5 0
3 years ago
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