Can i get some help with this?

Mathematics

1 answer:

liberstina [14]3 years ago

7 0

Answer:

Look at the image, pls give brainliest!

Step-by-step explanation:

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HELP NEEDED PLEASE!!!! This math question confuses me. I thought the line didn't pass through any other point but I cant figure

Vanyuwa [196]

Answer:

Step-by-step explanation:

So wiggly, remember that slope is change in y/change in x, or in simpler terms, y/x. Thinking of this, y/x must simplyfy to -3. Or, you can think of it as -3/1.

So know that we have rewrote this as a slope of -3/1, lets use it. Where do we start? Well, we must start at point A, which is at 2 x and 7 y.

Now, going to the RIGHT(+1x) and going DOWN(-3y) we will go from 2x and 7y to 3x and 4y.

Are we on a point yet? Nope, lets do this again.

Now going to RIGHT again(+1x) and going DOWN again(-3y) we will go from 13x and 4y to 4x and 1y.

Are we on a point yet? Still no, lets try this one more time.

Now going to RIGHT again(+1x) and going DOWN again(-3y) we will go from 4x and 1y to 5x and -2y.

Are we on a point? YUP. We cna see that point B is at 5x and -2y.

Hope you get it right ;)

4 0

3 years ago

Use the Parabola tool to graph the quadratic function. f(x)=2x^2−12x+19 Graph the parabola by first plotting its vertex and then

Debora [2.8K]

To find the vertex of our parabola, we are going to use the vertex formula: For a quadratic of the form $f(x)=x^2+bx+c$ it vertex $(h,k)$ is given by $h= \frac{-b}{2a}$ , $k=f(h)$ .
We can infet from our parabola that $a=2$ and $b=-12$ . So lets replace those values in our formula:
$h= \frac{-b}{2a}$
$h= \frac{-(-12)}{2(2)}$
$h= \frac{12}{4}$
$h=3$
$k=f(h)=2(3)^2-12(3)+19$
$k=2(9)-36+19$
$k=18-17$
$k=1$
The vertex $(h,k)$ of our parabola is $(3,1)$

Now to find our second point, we are going to evaluate our parabola at $x=0$
$f(0)=2(0)^2-12(0)+19$
$f(0)=0+0+19$
$f(0)=19$
Our second point is $(0,19)$

We can conclude that we can graph the parabola $f(x)=2x^2-12x+19$ using its vertex $(3,1)$ and the point $(0,19)$ as follows: