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3 years ago

Find the value of x

Mathematics

1 answer:

german3 years ago

3 0

Answer: x : 7

Step-by-step explanation:

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Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations. Hint: Use

QveST [7]

$\bf 27\implies 3^3\\\\
i^3\implies i\cdot i\cdot i\implies i^2\cdot i\implies -1\cdot i\implies -i\\\\
-----------------------------\\\\
x^3-27i=0\implies x^3+3^3(-i)=0\implies x^3+(3^3i^3)=0
\\\\\\
x^3+(3i)^3=0\\\\
-----------------------------\\\\
\textit{difference of cubes}
\\ \quad \\
a^3+b^3 = (a+b)(a^2-ab+b^2)\qquad
(a+b)(a^2-ab+b^2)= a^3+b^3\\\\
-----------------------------\\\\$

$\bf (x+3i)[x^2-3ix+(3i)^2]=0\implies 
\begin{cases}
x+3i=0\implies \boxed{x=-3i}\\\\
x^2-3ix+(3i)^2=0
\end{cases}
\\\\\\
\textit{now, for the second one, we'd need the quadratic formula}
\\\\\\
x^2-3ix+(3i)^2=0\implies x^2-3ix+(3^2i^2)=0
$

$\bf x^2-3ix+(-9)=0\implies x^2-3ix-9=0
\\\\\\
\textit{quadratic formula}\\\\
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}\implies x=\cfrac{3i\pm\sqrt{(-3i)^2-4(1)(-9)}}{2(1)}
\\\\\\
x=\cfrac{3i\pm\sqrt{(-3)^2i^2+36}}{2}\implies x=\cfrac{3i\pm\sqrt{-9+36}}{2}
\\\\\\
x=\cfrac{3i\pm\sqrt{27}}{2}\implies \boxed{x=\cfrac{3i\pm 3\sqrt{3}}{2}}$

7 0

3 years ago

Find area and perimeter!!!!!WILL GET BRAINLIEST !!!!!

kifflom [539]

Area: 9•6= 54ft sq Perimeter 9+9+6+6= 30ft

7 0

2 years ago

Read 2 more answers

Please solve this for me bc I’m too dumb.

oee [108]

Answer:

600 Beans

Step-by-step explanation:

7 0

2 years ago

Need an answer show work please thank you

d1i1m1o1n [39]

Answer:

$\text{C. }1$

Step-by-step explanation:

In the question, we're given that the notation $\#\#(a,b,c)$ produces a number $a$ less than the product of $b$ and $c$ raised to the $a$ power. Let the number produced be $n$ . As a mathematical equation, we can write this production as $n=(bc)^a-a$

For $\#\#(2, 5, x)$ , we can assign:

$a\implies 2$
$b\implies 5$
$c\implies x$

Substituting these values into $n=(bc)^a-a$ , we get:

$23=(5x)^2-2$

Add 2 to both sides:

$25=(5x)^2$

Take the square root of both sides:

$5=|5x|$

For $y=|z|$ , there are two cases:

$\begin{cases}y=z,\\y=-z\end{cases}$

Therefore, we have:

$\begin{cases}5=5x, x=\boxed{1}\\5=-(5x), 5=-5x, x=\boxed{-1}}\end{cases}$

The only answer choice applicable is $\boxed{\text{C. }1}$ .

7 0

2 years ago

Easy 10 points and brainliest :)

Llana [10]

Answer:

on the x-axis

Step-by-step explanation:

If x is less than 0, that means it's to the left of the origin, and if y = 0, then that means the point lies on the x-axis. Hence, (x,y) is on the x-axis.

Cheers.

4 0

3 years ago

Find the value of x ​

Find the value of x