Answer:
10 and 12
Step-by-step explanation:
let the consecutive even integers be n and n + 2 , then
n² - 64 = 3(n + 2) ← distribute parenthesis
n² - 64 = 3n + 6 ( subtract 3n + 6 from both sides )
n² - 3n - 70 = 0 ← in standard form
(n - 10)(n + 7) = 0 ← in factored form
Equate each factor to zero and solve for n
n - 10 = 0 ⇒ n = 10
n + 7 = 0 ⇒ n = - 7
Since n must be a positive even integer then n = 10 and n + 2 = 10 + 2 = 12
The 2 numbers are 10 and 12
Answer:
x+20
Step-by-step explanation:
As we can see n the diagram, there are parallel traversals and one line, and the two angles given are same-side interior angles. We know that when there is parallel traversal, and we have same side interiors, the sum of the measure of the two angles are supplementary. Supplementary means 180 degrees, or a straight line.
So we plug everything in and we have 4x+5x=180 degrees
4x+5x=9x, so 9x=180
We divide by 9 on both sides to get the value of x, which is 20
Hope it helps!
Answer:
6, -4
Step-by-step explanation:
abs(-1+x)=5
-1+x=5 and -1+x=-5
-------------------------
-1+x=5
x=5-(-1)=5+1=6
-------------------
-1+x=-5
x=-5-(-1)=-5+1=-4
Answer:
![312.5\pi \text{ km}^3\approx 981.75\text{ km}^3](https://tex.z-dn.net/?f=312.5%5Cpi%20%5Ctext%7B%20km%7D%5E3%5Capprox%20981.75%5Ctext%7B%20km%7D%5E3)
Step-by-step explanation:
We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.
Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.
Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.
, where,
r = Radius of cylinder,
h = height of the cylinder.
Upon substituting our given values in volume formula we will get,
![\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20a%20semicircular%20cylinder%7D%3D%5Cfrac%7B%5Cpi%20%285%5Ctext%7B%20km%7D%29%5E2%2A25%5Ctext%7B%20km%7D%7D%7B2%7D)
![\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20a%20semicircular%20cylinder%7D%3D%5Cfrac%7B%5Cpi%2A25%5Ctext%7B%20km%7D%5E2%2A25%5Ctext%7B%20km%7D%7D%7B2%7D)
![\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20a%20semicircular%20cylinder%7D%3D%5Cfrac%7B%5Cpi%2A625%5Ctext%7B%20km%7D%5E3%7D%7B2%7D)
![\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20a%20semicircular%20cylinder%7D%3D%5Cpi%2A312.5%5Ctext%7B%20km%7D%5E3)
![\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20a%20semicircular%20cylinder%7D%3D%5Cpi%2A312.5%5Ctext%7B%20km%7D%5E3)
![\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20a%20semicircular%20cylinder%7D%3D981.74770%5Ctext%7B%20km%7D%5E3)
Therefore, the volume of earth removed to build the three tunnels is
.
Hope this helps the picture explains how to do it hope its useful:)