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saul85 [17]
3 years ago
11

Find the solution to this system of equations x+y=1 2x-y+z=1 x+2y+z=8/3

Mathematics
1 answer:
drek231 [11]3 years ago
4 0

9514 1404 393

Answer:

  (x, y, z) = (1/3, 2/3, 1)

Step-by-step explanation:

We can use the first equation to write an expression for x that can be substituted into the other equations.

  x = 1 -y

  2(1 -y) -y +z = 1   ⇒   -3y +z = -1

  (1 -y) +2y +z = 8/3   ⇒   y +z = 5/3

Subtracting the first of these equations from the second gives ...

  (y +z) -(-3y +z) = (5/3) -(-1)

  4y = 8/3

  y = 2/3

  z = 5/3 -y = 1

  x = 1 -y = 1/3

The solution is (x, y, z) = (1/3, 2/3, 1).

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VMariaS [17]

Answer:

(-3,-2)

Step-by-step explanation:

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substitute the value of x into an equation

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multiply 3 to 2. and. 3 to 5/2y

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minus 6 to 5 and. add 15/2y to -7y

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substitute the value of -2 into an equation

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3 0
3 years ago
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Answer:

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Step-by-step explanation:

first, we convert the mixed fractions to improper fractions,

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so then we find what -\frac{3}{7}\div-\frac{15}{14}

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3 years ago
What is 2+2... your welcome
irina1246 [14]
4 duh ....... 2+2=4........................
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