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saul85 [17]
3 years ago
11

Find the solution to this system of equations x+y=1 2x-y+z=1 x+2y+z=8/3

Mathematics
1 answer:
drek231 [11]3 years ago
4 0

9514 1404 393

Answer:

  (x, y, z) = (1/3, 2/3, 1)

Step-by-step explanation:

We can use the first equation to write an expression for x that can be substituted into the other equations.

  x = 1 -y

  2(1 -y) -y +z = 1   ⇒   -3y +z = -1

  (1 -y) +2y +z = 8/3   ⇒   y +z = 5/3

Subtracting the first of these equations from the second gives ...

  (y +z) -(-3y +z) = (5/3) -(-1)

  4y = 8/3

  y = 2/3

  z = 5/3 -y = 1

  x = 1 -y = 1/3

The solution is (x, y, z) = (1/3, 2/3, 1).

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Rafael is taking a test that contains a section of 12 true-false questions. How many of the possible groups of answers to these
Klio2033 [76]
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8 0
3 years ago
-3x-5y=9<br> 5x + 5y=-15
cestrela7 [59]

Hello from MrBillDoesMath!

Answer:

x = -3, y = 0

Discussion:

5x + 5y = -15  =>

x + y = -3        =>           (divide both sides by 5)

x + y - y = -3 -y    =>      (subtract y from both sides)

x = -3 - y  

Substitute x = -3 - y   into the top equation:

-3x - 5y = -9 =>

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(-3)(-3) + (-3)(-y) - 5y  = 9 =>

9    + 3y - 5y = 9            =>      (  -*-   is a + number)

9 -2y = 9      =>

9 - 9 -2y  = 9 - 9     =>      (subtract 9 from both sides)

-2y = 0            =>

y = 0

Since x = -3 -y, x = -3 - 0 = =3


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


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4 years ago
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777dan777 [17]
The answer to this is 4 and thanks for the points
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