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SOVA2 [1]
3 years ago
14

Paul had some candy to give to his three children. He first took four pieces for himself and then evenly divided the rest among

his children. Each child received two pieces. With how many pieces did he
start?
Mathematics
2 answers:
Vesna [10]3 years ago
6 0
He started out with 10 pieces
jekas [21]3 years ago
3 0

Answer:

10 pieces

Step-by-step explanation:

Work backwards

Multiply 3 by 2 to get 6

Add 4 to 6 to get 10

Check:

10 - 4 = 6

6/3 = 2

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Abc Which type of rhetorical appeal is used when an author attempts to create strong feelings in the audience? O ethos imagery O
andrew11 [14]

Answer: good question

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2 years ago
Find the area of the triangle, also am I correct???
Ierofanga [76]

Answer:

The area of the triangle is 10.92 cm².

Step-by-step explanation:

The formula for the area of a triangle is

A=\frac{1}{2}bh

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3 0
3 years ago
Read 2 more answers
Please answer this correctly
liraira [26]
Answer:
2156/9

Explanation:
The question states all the necessary values that we need for the ratio. The company created 2156 board games and 9 card games.

However, what we need to pay attention to here is the order of the ratio.

Because the question is “What is the ratio of the number of board games to the number of card games”, we know that we need to write the ratio so the number of board games is first.

Additionally, ratios can also be written like fractions. The first number of the ratio would be the top number/numerator in fraction form.

Therefore, the ratio of the number of board games to the number of card games is 2156:9

I hope this helps!
6 0
3 years ago
Read 2 more answers
A ship leaves port at 10 miles per hour, with a heading of N 35° W. There is a warning buoy located 5 miles directly north of th
Leno4ka [110]

The value of the angle subtended by the distance of the buoy from the

port is given by sine and cosine rule.

  • The bearing of the buoy from the is approximately <u>307.35°</u>

Reasons:

Location from which the ship sails = Port

The speed of the ship = 10 mph

Direction of the ship = N35°W

Location of the warning buoy = 5 miles north of the port

Required: The bearing of the warning buoy from the ship after 7.5 hours.

Solution:

The distance travelled by the ship = 7.5 hours × 10 mph = 75 miles

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Where;

a = The distance between the ship and the buoy

b = The distance between the ship and the port = 75 miles

c = The distance between the buoy and the port = 5 miles

Angle ∠A = The angle between the ship and the buoy = The bearing of the ship = 35°

Which gives;

a = √(75² + 5² - 2 × 75 × 5 × cos(35°))

By sine rule, we have;

\displaystyle \frac{a}{sin(A)} = \mathbf{ \frac{b}{sin(B)}}

Therefore;

\displaystyle sin(B)= \frac{b \cdot sin(A)}{a}

Which gives;

\displaystyle sin(B) = \mathbf{\frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }}

\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx 37.32^{\circ}

Similarly, we can get;

\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx \mathbf{ 142.68^{\circ}}

The angle subtended by the distance of the buoy from the port, <em>C</em> is therefore;

C ≈ 180° - 142.68° - 35° ≈ 2.32°

By alternate interior angles, we have;

The bearing of the warning buoy as seen from the ship is therefore;

Bearing of buoy ≈ 270° + 35° + 2.32° ≈ <u>307.35°</u>

Learn more about bearing in mathematics here:

brainly.com/question/23427938

5 0
2 years ago
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