Its d beacuse its the only true statement abot the liquads lol
You could argue that any solution with water in it has an equilibrium in it of some sort. If a solution is over saturated there is an equilibrium between the dissociated and solid solute (for example NaCl(s)⇄Na⁺(aq)+Cl⁻(aq) when in water). Even if the solution is not over saturated, water always has the reaction 2H₂O(l)⇄H₃O⁺(aq)+OH⁻(aq) since water can act as both an acid and a base (this reaction is also always at equilibrium and the equilibrium constant is 1×10⁻¹⁴).
Since we usually ignore the autoionization of water (unless dealing with acid base chemistry), I think the answer your teacher is looking for is over saturated solutions.
I hope this helps. Let me know if anything is unclear or if you need a different answer.
Answer:
[A]²
Explanation:
Since the formation is independent of D, D is 0 order.
Since a quadruples when it is doubled it can be written as
2A^X= 4
To find the unknown power we can assume A= 1 to make the math simple. So When a = 2 (Because you doubled it) raised to X power it will equal 4
so the unknown power is 2
Making the rate law
[a]²[b]⁰
or simply just
[A]²
I don’t know this is so sad lo lol
