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Flauer [41]
3 years ago
9

C2H5OH is able to dissociate in water to conduct an electric current. This compound could be classified as

Chemistry
1 answer:
nekit [7.7K]3 years ago
7 0
The fact that when in solution <span>C</span>₂<span>H</span>₅<span>OH conducts electricity means that it is an electrolyte so you can automatically cross out A and C (the definition of an electrolyte is a substance that will conduct electricity when in a solution).  I think the correct answer is B due to the -OH group (the - indicates a covalent bond) which allows the molecule to give up a proton (H</span>⁺).
 I hope this helps.  Let me know if anything is unclear.
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Hey, anyone got discord? I'm new to discord. Add me Smile#4741​
baherus [9]

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8 0
3 years ago
Read 2 more answers
How much heat energy would be released if 78.1 g of water at 0.00 °c were converted to ice at −57.1 °c. give your answer as a po
kolezko [41]
To convert 78.1 g of water at 0° C to Ice at -57.1°C; we can do it in steps;
1. Water at 0°C to ice at 0°C
The heat of fusion of ice is 334 J/g; 
Heat = 78.1 × 334 = 26085.4 Joules
2. Ice at 0°C to -57.1°C 
Specific heat of ice is 2.108 J/g
Heat = 78.1 × 2.108 J/g = 164.6348 Joules
Thus the total heat energy released will be; 26085.4 + 164.6348 
 = 26250.0348 J or 26.250 kJ
3 0
3 years ago
50 points I need help on this whole work sheet about converting moles
kozerog [31]

Answer:

Explanation:

11)

Answer:

9.08 mol

Given data:

Number of moles of P₂O₅ = ?

Number of moles of O₂ = 22.7 mol

Solution:

Chemical equation:

4P +  5O₂    →    2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

                               O₂      :        P₂O₅

                                 5      :          2

                                 22.7  :        2/5×22.7 = 9.08

12)

Answer:

7 mol

Given data:

Number of moles of P₂O₅ = ?

Number of moles of P = 14 mol

Solution:

Chemical equation:

4P +  5O₂    →    2P₂O₅

Now we will compare the moles of P₂O₅ with P.

                               P        :        P₂O₅

                               4        :          2

                                14      :        2/4×14 = 7

13)

Answer:

76.25 mol

Given data:

Number of moles of P =  61 mol

Number of moles of O₂ react = ?

Solution:

Chemical equation:

4P +  5O₂    →    2P₂O₅

Now we will compare the moles of P with O₂.

                                  P         :        O₂

                                  4          :          5

                                 61          :        5/4×61 = 76.25

14)

Answer:

1.25 mol

Given data:

Number of moles of P₂O₅ = 0.5 mol

Number of moles of O₂ needed = ?

Solution:

Chemical equation:

4P +  5O₂    →    2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

                                P₂O₅         :        O₂

                                  2            :          5

                                0.5          :        5/2×0.5 = 1.25

15)

Answer:

20 mol

Given data:

Number of moles of P₂O₅ = 8 mol

Number of moles of O₂ needed = ?

Solution:

Chemical equation:

4P +  5O₂    →    2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

                                P₂O₅       :        O₂

                                  2            :          5

                                  8            :       5/2×8 = 20

16)

Answer:

12 mol

Given data:

Number of moles of silver made = ?

Number of moles of Ag₂O = 6 mol

Solution:

Chemical equation:

2Ag₂O   →   4Ag + O₂

Now we will compare the moles of Ag with Ag₂O .

                       Ag₂O      :       Ag

                           2         :        4

                           6          :        4/2×6 = 12

17)

Answer:

25 mol

Given data:

Number of moles of silver made = ?

Number of moles of O₂ produced = 6.25 mol

Solution:

Chemical equation:

2Ag₂O   →   4Ag + O₂

Now we will compare the moles of Ag with O₂ .

                          O₂             :       Ag

                           1               :        4

                           6.25          :      4×6.25 = 25

18)

Answer:

9.8 mol

Given data:

Number of moles of silver made = ?

Number of moles of O₂ produced = 2.45 mol

Solution:

Chemical equation:

2Ag₂O   →   4Ag + O₂

Now we will compare the moles of Ag with O₂ .

                          O₂             :       Ag

                           1               :        4

                          2.45          :      4×2.45 = 9.8

19)

Answer:

4.4 mol

Given data:

Number of moles of silver oxide required = ?

Number of moles of O₂ produced = 2.2 mol

Solution:

Chemical equation:

2Ag₂O   →   4Ag + O₂

Now we will compare the moles Ag₂O of with O₂ .

                           O₂            :       Ag₂O

                           1               :         2

                          2.2            :        2×2.2  = 4.4

20)

Answer:

1.5 mol

Given data:

Number of moles of silver oxide required = ?

Number of moles of O₂ produced = 0.75 mol

Solution:

Chemical equation:

2Ag₂O   →   4Ag + O₂

Now we will compare the moles Ag₂O of with O₂ .

                           O₂            :         Ag₂O

                           1               :            2

                          0.75            :        2×0.75 = 1.5

8 0
4 years ago
True or false?? All atoms of the same element have the same atomic mass
AnnyKZ [126]

Answer:

False

Explanation:

8 0
3 years ago
Read 2 more answers
13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the
wariber [46]

Answer:

13. 2.60 L.

14. 2.40 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

<em>13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the  pressure  is increased to 1.25 atm.</em>

P₁ = 0.755 atm, V₁ = 4.31 L.

P₂= 1.25 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (0.755 atm)(4.31 L)/(1.25 atm) = 2.60 L.

<em>14. 600.0 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at 2.00  at m.</em>

P₁ = 8.0 atm, V₁ = 600.0 mL.

P₂= 2.0 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (8.0 atm)(600.0 mL)/(2.0 atm) = 2400/0 mL = 2.40 L.

3 0
3 years ago
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