Yes it is a right triangle
He should use the Pythagorean Theorem to find the missing length.
Since KT is tangent to the circle and TL reaches the center of circle L, the measure of angle LTK is 90 degrees. This means that triangle LTK is a right triangle which means the Pythagorean Theorem can be used.
So,
TL²+(12)²=(13)²
=> TL²+144=169
=> TL²=25
=> TL = 5
Therefore, the radius of circle L is 5 feet.
In this problem, there are two congruent right triangles: triangle XCA and triangle XBC, where the hypotenuse are XA and XB respectively. Considering triangle XBC, XB = radius = 17, and BC = 30 / 2 = 15. By pythagorean theorem, XC = sqrt(17^2 - 15^2) = sqrt(289 - 225) = sqrt(64) = 8 units.
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Answer:
Slope <em>m</em> = 6
y-intercept <em>b</em> = -5
General Formulas and Concepts:
<u>Algebra I</u>
Slope-Intercept Form: y = mx + b
- m - slope
- b - y-intercept
Step-by-step explanation:
<u>Step 1: Define</u>
[Slope-Intercept Form] y = 6x - 5
<u>Step 2: Break Function</u>
<em>Identify Parts</em>
Slope <em>m</em> = 6
y-intercept <em>b</em> = -5
Since supplementary angles equal 180. (2x+15) = 45, which can be found by subtracting 135 from 180. This means that x = 15. And since angle 1 corresponds to the previous angle, we can deduce that angle 1 = 45.
