The equation for a quadratic is as follows:
y = ax^2+bx+c
The first variable “a” determines whether the parabola opens up or down
The squared allows the equation to look like the parabola swoop when graphed.
The c term is the constant term
Answer:
C.
Step-by-step explanation:
Simply multiply 50 by 3/8
Answer:
y=3x+3
Step-by-step explanation:
To find the slope, find two points and use the rise over run.
Some points you can use are (0, 3) and (1, 6)
The rise is 3 and the run is 1.
3/1 = 1.
The slope is 3.
To find the y-intercept, find the point where x = 0.
(0, 3)
The y-intercept is 3.
Now you can write an equation.
y=mx+b
m is the slope and b is the y-intercept.
y=3x+3
Answer: m=−3
Step-by-step explanation: −40−2(3m+1/2)=7m−2
−40+(−2)(3m)+(−2)(1/2)=7m+−2
−40+−6m+−1=7m+−2
(−6m)+(−40+−1)=7m−2
−6m+−41=7m−2
−6m−41−7m=7m−2−7m
−13m−41+41=−2+41
−13m/−13=39/−13
m=−3
What mistake I guess Keith did make is he subtracted 2 from -39 which equaled to -37 which caused him divide -37 by 13 when it should have been 39 divided by 13 because he should have left 39 alone and not have subtracted 2 from it also it should not have been negative basically what I'm trying to say is that he did his division and subtraction wrong.
The gcf of -18m and 27 is -9 if not then positive 9, but if you want me to also solve the equation its -18m + 27 is -9(2m - 3) i hope it helps!
